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3 years ago

Two or more organs working together form

1 answer:

6 0

ORGANS. Tissues are grouped together in the body to form organs. These include the brain, heart, lungs, kidneys, and liver. Each body organ has a specific shape and is made up of different types of tissue that work together.

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Scientists observed a rocky, rotating object orbiting in space. It was 250 km wide. The rocky object was located several times f

mote1985 [20]

The rocky object orbiting in space is most likely referred to as an asteroid.

<h3>What is an Asteroid?</h3>

This is referred to a rocky object which revolve around the sun and are considered too small to be called a planet.

Asteroids was observed with the use of a telescope and is around 250 km wide thereby making it the most appropriate choice.

Read more about Asteroids here brainly.com/question/11996385

4 0

3 years ago

A ball is gently dropped from a height of 20 m. If its velocity Increases uniformly at the rate of 10 m s2, with what velocity w

Pie

Answer:

20 m/s

Explanation:

Height (s)= 20m

acceleration (a) = 10 m/s^2

v=?

we know,

V^2= U^2 + 2as. (U is initial velocity)

or,. V^2 = 0 + 2 × 10 × 20

or, V^2 = 400

or,. V = 20 m/s

5 0

2 years ago

Read 2 more answers

A) A real object 4.0 cm high stands 30.0 cm in front of a converging lens of focal length 23 cm. Find the image distance, the im

vfiekz [6]

Explanation:

Given that,

Height of object = 4.0 cm

Distance of the object u= -30.0 cm

Focal length = 23 cm

We need to calculate the image distance

Using lens's formula

$\dfrac{1}{v}-\dfrac{1}{u}=\dfrac{1}{f}$

Where, u = object distance

v = image distance

f = focal length

Put the value into the formula

$\dfrac{1}{v}-\dfrac{1}{-30}=\dfrac{1}{23}$

$\dfrac{1}{v}=\dfrac{1}{23}-\dfrac{1}{30}$

$\dfrac{1}{v}=\dfrac{7}{690}$

$v=98.57\ cm$

We need to calculate the height of the image

Using formula of height

$\dfrac{h'}{h}=\dfrac{-v}{u}$

Where, h' = height of image

h = height of object

$\dfrac{h'}{4}=\dfrac{-98.57}{-30}$

$h'=\dfrac{98.57\times4}{30}$

$h'=13.14\ cm$

The image is real and inverted.

(b). Now, object distance u = 13.0 cm

We need to calculate the image distance

Using lens's formula

$\dfrac{1}{v}-\dfrac{1}{u}=\dfrac{1}{f}$

Put the value into the formula

$\dfrac{1}{v}=\dfrac{1}{23}-\dfrac{1}{13.0}$

$\dfrac{1}{v}=-\dfrac{10}{299}$

$v=-29.9\ cm$

We need to calculate the height of the image

$\dfrac{h'}{4}=\dfrac{-(-29.9)}{-13.0}$

$h=-\dfrac{29.9\times4}{13.0}$

$h=-9.2\ cm$

The image is virtual and erect.

Hence, This is required solution.

6 0

3 years ago

The use of a simple machine will reduce the amount of work needed to move an object.true false

Eddi Din [679]

False they simple machines do not reduce the amount of work you do it would just reduce the amount of force you use.

3 0

3 years ago

If a cheetah could maintain its top speed of 120 km/h for 20 minutes, how far would it run?

GuDViN [60]

Alright. If it’s running at a constant speed of 120 km/h, in one hour it will have traveled 120 kilometers. hence “kilometers per hour”

20 minutes is 1/3 of an hour so 120/3 will be 40

therefore, in 20 minutes the cheetah would’ve ran 40km if it maintained 120km/h for 20 minutes.

3 0

3 years ago