A constant torque of 29.1 N · m is applied to a grindstone whose moment of inertia is 0.142 kg · m2 . Using energy principles, a
nd neglecting friction, find the angular speed after the grindstone has made 14.1 rev, assuming it started from rest. Answer in units of rev/s.
1 answer:
Answer:
76.0198 rev/sec
Explanation:
Given
Torque ( T ) = 29.1 N
Moment of inertia = 0.142 kg.m²
Ф = 14.1 rev
F = 
F = T ΔФ
w² =( 2TΔФ)/I = 
w = √5779.01 = 76.0198 rev/sec
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