1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Dmitrij [34]
3 years ago
11

Explain the relationships between gravity, mass, and distance. please write a paragraph

Physics
1 answer:
Gelneren [198K]3 years ago
4 0
Gravity is an attractive force which every object with mass exerts. The "relationship" tells us how much gravity is exerted between two objects. The formula is F  g =  \frac{G M_1 M_2}{D^2}. what this says is that in order to figure out Fg(Force of gravity), we must take into account G( gravitational constant 6.67x10^-11) x M1(mass 1) x M2(mass2) / d^2(ditance squared). Mass is measured in Kg(kilograms). G never changes,and Fg is in Newtons. In terms of planets, you must take into account the radius of the planet within your distance. In Layman terms, You use all three to figure out how much gravity one object exerts on another and vice versa.
You might be interested in
Which quantities are scalars?​
Gemiola [76]

Answer:

Speed and distance are examples of scalar quantities.

6 0
3 years ago
Read 2 more answers
Identify whether each item is an example of science or technology.
Readme [11.4K]
Windmill- Science
Maglev Train- Technology

Hopefully these are right
7 0
3 years ago
A 0.5 kg block of aluminum (caluminum=900J/kg⋅∘C) is heated to 200∘C. The block is then quickly placed in an insulated tub of co
Genrish500 [490]

Answer: When 1.0kg of aluminium block is used, the final temperature of the mixture will be T = 36.2∘C

If 1.0kg copper block is used, T of the mixture will be = 17.4∘C

If 100g (0.1kg) of ice at 0∘C is used, T will be = 64.9∘C

If 25g (0.025Kg) of ice is used, T will be= 147.1∘C

Explanation:

H = mcΘ

heat lost by block = heat gained by water

m₁c₁Θ₁ = m₂c₂Θ₂ where m₁ is mass of aluminium, m₂ is mass of water, c₁ is cAluminium, c₂ is cWater, Θ₁ is temperature change for aluminium, Θ₂ is temperature change for water.

0.5*900*(200-20) = m₁*4186*(20-0)

m₁ = 450*180/83270

<em>m₁ = 0.973kg</em>

<em>when 1.0kg of aluminium block is used, the final temperature of the mixture will be </em><em>T</em>

heat lost by block = heat gained by water

1.0*900*(200-T) = 0.973*4186*(T-0)

180000 - 900T = 4073T

4973T = 180000

T = 180000/4973 = 36.2∘C

<em>If 1.0kg copper block is used, T of the mixture will be</em>

heat lost by block = heat gained by water

1.0*387*(200-T) = 0.973*4186*(T-0)

77400 - 387T = 4073T

4460T = 77400

T = 77400/4460 = 17.4∘C

<em>If 100g (0.1kg) of ice at 0∘C is used, T will be</em>

<em>heat lost by block = heat gained by water + heat used in melting ice to form water at 0∘C</em>

heat used in melting 0.1kg of ice, H = ml, where l= 33600J/Kg

0.5*900*(200-T) = 0.1*4186*(T-0) + 0.1*33600J/Kg

90000 - 450T =  418.6T + 33600

418.6T + 450T = 90000 - 33600

868.6T = 56400

T = 56400/868.6 = 64.9∘C

If 25g (0.025Kg) of ice is used, T will be

0.5*900*(200-T) = 0.025*4186*(T-0) + 0.025*33600J/Kg

90000 - 450T =  104.65T + 8400

104.65T + 450T = 90000 - 8400

554.65T = 81600

T = 81600/554.65 = 147.1∘C

7 0
3 years ago
Jupiter is a much more massive planet than Earth. What would happen to a person’s mass and weight if he were on Jupiter?
Harrizon [31]
There would be no mass or weight and he would float away
5 0
3 years ago
Read 2 more answers
A coin of mass m rests on a turntable a distance r from the axis of rotation. The turntable rotates with a frequency of f. What
Crank

Answer:

\mu = \frac{r (2\pi f)^{2}}{g}

Explanation:

N = normal force acting on the coin

Normal force in the upward direction balances the weight of the coin, hence

N = mg

f = frequency of rotation

Angular velocity of turntable is hence given as

w = 2\pi f

r = distance from the axis of rotation

\mu = minimum coefficient of static friction

static frictional force is given as

f = \mu N\\f = \mu mg

The  static frictional force provides the necessary centripetal force , hence

Centripetal force = Static frictional force

m r w^{2} = \mu mg\\r w^{2} = \mu g\\\\\mu = \frac{r w^{2}}{g} \\\mu = \frac{r (2\pi f)^{2}}{g}

3 0
3 years ago
Other questions:
  • Which of the following is a vector quantity?
    13·1 answer
  • Rewrite this formula to solve for GGi: DX=fL/GGi
    5·1 answer
  • An 80 kilogram skier slides on waxed skis along a horizontal surface of snow at a constant velocity while pushing with his poles
    12·1 answer
  • What do we call the side of the Earth that faces the sun?
    14·1 answer
  • The Thomson model of a hydrogen atom is a sphere of positive charge with an electron (a point charge) at its center. The total p
    9·1 answer
  • The 243000-lb space-shuttle orbiter touches down at about 236 mi/hr. The drag chute is deployed at 189 mi/hr, the wheel brakes a
    8·1 answer
  • What lifelong benifits can be at gained by participating in tract and field?​
    12·1 answer
  • What is the radius of an automobile tire that turns with a period of 0.091 s and has a linear
    5·1 answer
  • This happens because the.....particles are most likely to escape from the liquid, causing the temperature of the liquid to.....
    15·1 answer
  • If you break from the speed in part (c) and then start again from rest, how fast will you be able to drive?
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!