The efficiency of an average gasoline-powered car is about 20%. This means

Physics

2 answers:

Dennis_Churaev [7]2 years ago

7 0

Ayy I really hope the answer the last person gave you was right bc I have no idea

nydimaria [60]2 years ago

4 0

Answer:

This means C.the car uses 20% of the energy store in the gasoline for motion.

Explanation:

I hope this helps.

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A 0.700-kg particle has a speed of 1.90 m/s at point circled A and kinetic energy of 7.20 J at point circled B. (a) What is its

Savatey [412]

Answer:

a). $E_{kA}=1.2635 J$

b). $V_{B}=4.535\frac{m}{s}$

c). Δ $E_{t}=8.4635 J$

Explanation:

ΔE=kinetic energy

a).

$E_{kA}=\frac{1}{2}*m*v_{A} ^{2} \\ v_{A}=1.9 \frac{m}{s}\\ m=0.70kg\\E_{kA}=\frac{1}{2}*0.70kg*(1.9 \frac{m}{s})^{2} \\E_{kA}=1.2635 J$

b).

$E_{kB}=\frac{1}{2}*m*v_{B} ^{2}$

$V_{B}^{2}=\frac{E_{kB}*2}{m} \\V_{B}=\sqrt{\frac{E_{kB}*2}{m}} \\V_{B}=\sqrt{\frac{7.2J*2}{0.70kg}} \\V_{B}=4.53 \frac{m}{s}$

c).

net work= EkA+EkB

$E_{t}=E_{kA}+ E_{kB}\\E_{t}=1.2635J+7.2J\\E_{t}=8.4635J$

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3 years ago

An electric current flows through a parallel circuit. Which units tell you about the amount of electrons traveling in the circui

kompoz [17]

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of electrons, you'd need to know the length of time too.

It doesn't matter whether we're talking about a parallel or
series circuit.

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Two satellites, A and B are in different circular orbits

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