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3 years ago

HELP PLEASE WILL GIVE BRAINLIEST

Chemistry

1 answer:

Crank3 years ago

4 0

Answer:

Option D. Al is above H on the activity series.

Explanation:

The equation for the reaction is given below:

2Al + 6HBr —> 2AlBr₃ + 3H₂

The activity series gives us a background understanding of the reactivity of elements i.e how elements displace other elements when present in solution.

From the activity series of metals, we understood that metal higher in the series will displace those lower in the series.

Considering the equation given above, Al is higher than H in the activity series. Thus, the reaction will proceed as illustrated by the equation.

Therefore, we can conclude that the reaction will only occur if Al is higher than H in the activity series.

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3 years ago

What is the value of the equilibrium constant at 25 oC for the reaction between the pair: I2(s) and Br-(aq) Give your answer usi

insens350 [35]

Explanation:

Formula to calculate standard electrode potential is as follows.

$E^{o}_{cell} = E^{0}_{cathode} - E^{0}_{anode}$

= 0.535 - 1.065

= - 0.53 V

Also, it is known that relation between $E^{o}_{cell}$ and K is as follows.

$E^{o}_{cell} = \frac{RT}{nF} \times ln K$

ln K = $\frac{nFE^{0}_{cell}}{RT}$

Substituting the given values into the above formula as follows.

ln K = $\frac{nFE^{0}_{cell}}{RT}$

= $\frac{2 \times 96485 C mol^{-1} \times -0.53 V}{8.314 l atm/mol K \times 298 K} \times \frac{1 J}{1 V C}$

ln K = -41.28

K = $e^{-41.28}$

= $1 \times 10^{-18}$

Thus, we can conclude that the value of the equilibrium constant for the given reaction is $1 \times 10^{-18}$ .

5 0

3 years ago

The atomic particle with a charge of -1.6 x 10-19 C is

kobusy [5.1K]

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7 0

2 years ago

Read 2 more answers

Calculate the density of a solid if it has a mass of 8.47 g and a volume of 3.24 cms.

gtnhenbr [62]

Answer:

Density =2.614g/cms

Explanation:

Density = mass/volume

Density= 8.47g/3.24cms

3 0

3 years ago

Calculate the equilibrium constant at 25 ∘C for the reaction Fe(s)+2Ag+(aq)→Fe2+(aq)+2Ag(s)

Murrr4er [49]

Answer:

1.7 × 10 ^42

Explanation:

Using Nernst equation

E°cell = RT/nF Inq

at equilibrium

Q=K

E°cell = 0.0257 /n Ink= 0.0592/n log K

Fe2+(aq)+2e−→Fe(s) E∘= −0.45 V

Ag+aq)+e−→Ag(s) E∘= 0.80 V

Fe(s)+2Ag+(aq)→Fe2+(aq)+2Ag(s)

balance the reaction

Fe → Fe²⁺ + 2e⁻ reversing for oxidation E° = 0.45 v

2 Ag⁺ +2e⁻ → 2Ag

n = 2 moles and K = equilibrium constant

E° cell = 0.80 + 0.45 = 1.25 V

E° cell = (0.0592 / n) log K

substitute the value into the equations and solve for K

(1.25 × 2) / 0.0592 = log K

42.23 = log K

k = 10^ 42.23

K = 1.7 × 10 ^42

8 0

3 years ago