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3 years ago

Who else listens to sad music and think of something there not?

Chemistry

2 answers:

Likurg_2 [28]3 years ago

8 0

Answer:

Meeee:(

Explanation:

Dmitriy789 [7]3 years ago

6 0

Answer:

Yours truly..........

Explanation:

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Story:Mr Krabs created a secret ingredient for a breath mint that he thinks will "cure" the bad breath people get from eating cr

Daniel [21]

They had fresher breathe because their breathe may have been bad before.

3 0

3 years ago

Explain how Earth is heated through radiation.

sergiy2304 [10]

With this temperature the Earth Radiation will be centered on a Wavelength!

8 0

3 years ago

The Lewis diagram for BH2 is:

Luda [366]

Answer:

Electron pair geometry- trigonal planar

There is one lone pair around the boron atom

The geometry of BH2 is bent

Explanation:

The valence shell electron pair repulsion theory offers a frame work for determining the shape of molecules based on the number of electron pairs of the valence shell of the central atom in the molecule.

In BH2-, the central atom is boron. There is a lone pair on boron. Owing to the lone pair on boron, the molecular geometry of BH2 is bent.

4 0

3 years ago

In a process for producing acetic acid, oxygen gas is bubbled into acetaldehyde, CH3CHO, containing manganese(II) acetate (catal

grigory [225]

Answer: The mass of acetic acid that can be produced is 30.24 grams

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

For acetaldehyde:

Given mass of acetaldehyde = 22.2 g

Molar mass of acetaldehyde = 44 g/mol

Putting values in equation 1, we get:

$\text{Moles of acetaldehyde}=\frac{22.2g}{44g/mol}=0.504mol$

For oxygen gas:

Given mass of oxygen gas = 12.6 g

Molar mass of oxygen gas = 32 g/mol

Putting values in equation 1, we get:

$\text{Moles of oxygen gas}=\frac{12.6g}{32g/mol}=0.394mol$

The given chemical equation follows:

$2CH_3CHO(l)+O_2(g)\rightarrow 2CH_3COOH(l)$

By Stoichiometry of the reaction:

2 moles of acetaldehyde reacts with 1 mole of oxygen gas

So, 0.504 moles of acetaldehyde will react with = $\frac{1}{2}\times 0.504=0.252mol$ of oxygen gas

As, given amount of oxygen gas is more than the required amount. So, it is considered as an excess reagent.

Thus, acetaldehyde is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

2 moles of acetaldehyde produces 2 moles of acetic acid

So, 0.504 moles of acetaldehyde will produce = $\frac{2}{2}\times 0.504=0.504moles$ of acetic acid

Now, calculating the mass of acetic acid from equation 1, we get:

Molar mass of acetic acid = 60 g/mol

Moles of acetic acid = 0.504 moles

Putting values in equation 1, we get:

$0.504mol=\frac{\text{Mass of acetic acid}}{60g/mol}\\\\\text{Mass of acetic acid}=(0.504mol\times 60g/mol)=30.24g$

Hence, the mass of acetic acid that can be produced is 30.24 grams

8 0

3 years ago

Reduce the following molecular formulas to empirical formulas. Please help!

zvonat [6]

This is done by reducing each number by a common factor for each formula.

C3H6O6- all can be divided by 3 -> CH3O3 (you don't have to put a 1 for C, only if your teacher requests it. It is generally understood if not written)

H2O2- all can be divided by 2 -> H1O1 (had to put the 1's bc of the unintended language)

C8H8S2- all can be divided by 2 -> C4H4S

P5O15- all can be divided by 5- PO3

*****it is important to note that all numbers in the molecular formula are divided by the same thing to reduce them. decimals are never used in empirical formulas, only whole numbers.*****

3 0

3 years ago