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HACTEHA [7]
3 years ago
11

Ammonia enters an adiabatic compressor operating at steady state as saturated vapor at 300 kPa and exits at 1400 kPa, 140◦C. Kin

etic and potential energy effects are negligible. Determine:
a. power input required [kJ/kg]
b. isentropic compressor efficiency
c. rate of entropy production per unit mass [kJ/kg K] in the compressor

Engineering
1 answer:
hammer [34]3 years ago
8 0

Answer:

a. 149.74 KJ/KG

b. 97.9%

c. 0.81 kJ/kg K

Explanation:

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A CL soil is being used for compacted fill on a project. A sample of the compacted soil with a total volume of 1/30 ft3 weighs 4
Genrish500 [490]

Answer:

A. 0.4

B. 1.003

C. 0.83

Explanation:

The void ratio of a mixture is defined as the ratio of the volume of voids to volume of solids.

Total volume of soil = 1/30 ft3

= 1 ft3/30 * 0.0283 m3/1 ft3

= 9.43 x 10^-4 m3

Mass of water is in the soil = 20% * 4.8

= 0.96 pounds of water

= 0.96 * 0.454

= 0.44 kg

SG = density of substance/density of water

= 2.66 * 1 kg/l

Density of the soil = 2.660 kg/l

Mass of solid = 80 %

= 80% * 4.8 * 0.454

= 1.74 kg

Volume of solids = mass/density

= 1.74/2.66

= 6.63 l

= 6.63 x 10^-4 m3.

The volume of voids is found by adding the volume of water and the volume of air.

Total volume of soil = volume of (solids + voids)

9.43 x 10^-4 = 6.63 x 10^-4 + voids

Volume of voids = 2.8 x 10^-4 m3

A.

Void ratio = volume of void : volume of solids

= 2.8 : 6.63

= 0.4

B.

Y = (1 + w) * Gs * Yw * (1 + e)

Y = moist unit weight

Yw = unit weight of water

w = moisture content of the material

Gs = pecific gravity of the solid

e = void ratio

= (1 + 0.2) * 2.66 * 0.44 * (1 + 0.4)

= 1.003.

C.

gd = Y/(1 + w)

Or

= Gs * Yw * 1/(1 + e)

= 0.83.

6 0
3 years ago
Answer the question faster please
Juliette [100K]

Answer:

No

Explanation:

3 0
3 years ago
does anyone know how to get into an iPhone with an apple ID and password i bought an iPhone 2nd hand and i cant get into the pho
ELEN [110]
ANSWER:
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5 0
3 years ago
Read 2 more answers
Two semiconductor materials have exactly the same properties except material A has a bandgap energy of 0.90 eV and material B ha
AlekseyPX

Answer: hello your question is incomplete attached below is the complete question

answer : Ac = 5° , A_{f} = 2.5°

Explanation:

Bandgap energy for material A = 0.90 eV

Bandgap energy for material B = 1.10 eV

<u>Calculate the ratio of ni for Material B to Material B </u>

Total derivation ( d ) = d1 + d2

 d = A_{c} ( μ_{c} - 1 ) + A_{f} ( μ_{f} - 1 )  ---- ( 1 )

where : d = 1° , μ_{c} = 1.5 , μ_{f} = 1.6

Input values into equation 1 above

1° = 0.5Ac + 0.6Af  ---- ( 2 )

also d = d1 [ 1 - w/ w1 ] ------ ( 3 )

∴ d = Ac ( μ_{c} - 1 ) ( 1 - w/w1 )

  1° = Ac ( 1.5 - 1 ) ( 1 - 0.06/0.1 ) --- ( 4 )

resolving  equation ( 4 )

Ac = 5°

resolving equation ( 2 )

A_{f} = 2.5°

8 0
3 years ago
a horizontal jet of water (at 100c) that is 6 cm in diameter and has a velocity of 20 m/s is deflected by the vane as shown. if
Reptile [31]

The net resultant direct force and angle on the vane is created when the water jet exits the vane at position 2 with 92% of its initial velocity.

<h3>What is mean by velocity?</h3>
  • The speed at which a body or object is moving determines its direction of motion. A scalar quantity, speed is primarily. As a matter of fact, velocity is a vector quantity.
  • The rate at which distance changes is what it is. It measures the displacement's rate of change. A body's velocity is defined as its speed in a particular direction.
  • Velocity is a measure of how quickly a distance changes in relation to time. Having both magnitude and direction, velocity is a vector quantity.
  • The rate of change in a body's displacement with respect to time is referred to as velocity. In the SI, m/s is its unit.

Given,

External angle of Curved Vane = 158°

mean velocity at 1 = 12 m/s

Volumetric flow rate = 55 \mathrm{~m}^3 / \mathrm{h}=\frac{55}{3600} \mathrm{~m}^3 / \mathrm{s}$.

mean velocity at $2=12 \times 0.92=11.04 \mathrm{~m} / \mathrm{s}$

i) Force exerted in x - friction A C 1 =  Volume

F_{S_x} &=\rho A C_1\left[C_2 \cos \theta-C_1\right] \\

&=1000 \times \frac{55}{3600}\left[\left(11.04 \cos 158^{\circ}\right)-12\right]

i\rangle F_{\text {sc }}=\supseteq A c_1\left[C_2 \sin \theta\right] \\

&=1000 \times \frac{55}{3600} \times \text { TI. 04 } \sin (1589 \\

&F_{\text {syn }}=63.18 \mathrm{~N} \\

&\text { Angle } \Rightarrow \frac{F_{s y}}{F_{3 x}}-\tan \theta \\

&\tan \theta=\frac{63.18}{339.18}, \theta=160-10-5.3 \\

&\theta=\tan ^{-}\left(\frac{-63 \cdot 18}{339728}\right) \\

&\theta=-10.540^{\circ} \\

The complete question is:

A horizontal jet of water strikes a curved vane as shown in Figure C.1. The external angle of the curved vane is 158°.The mean velocity and volumetric flow rate of the water jet at position 1 are 12 m/s and 55 m³/h respectively. Due to friction, the water jet leaves the vane at position 2 with 92 % its original velocity.

(i) Direct force exerted by the water jet on the vane in the x - direction.

(ii) Direct force exerted by the water jet on the vane in the y - direction.

(ii) Net resultant direct force and angle on the vane.

To learn more about velocity, refer to:

brainly.com/question/24681896

#SPJ4

4 0
2 years ago
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