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2 years ago

A retail business, owned by share holders and having centralized decision making for their multiple store locations is called:

Engineering

1 answer:

lara [203]2 years ago

4 0

Answer:

An enterprise that produces goods or provides services, usually to make a profit.

Explanation:

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At an impaired driver checkpoint, the time required to conduct the impairment test varies (according to an exponential distribut

professor190 [17]

Answer:

Option (d) 2 min/veh

Explanation:

Data provided in the question:

Average time required = 60 seconds

Therefore,

The maximum capacity that can be accommodated on the system, μ = 60 veh/hr

Average Arrival rate, λ = 30 vehicles per hour

Now,

The average time spent by the vehicle is given as

⇒ $\frac{1}{\mu(1-\frac{\lambda}{\mu})}$

thus,

on substituting the respective values, we get

Average time spent by the vehicle = $\frac{1}{60(1-\frac{30}{60})}$

Average time spent by the vehicle = $\frac{1}{60(1-0.5)}$

Average time spent by the vehicle = $\frac{1}{60(0.5)}$

Average time spent by the vehicle = $\frac{1}{30}$ hr/veh

Average time spent by the vehicle = $\frac{1}{30}\times60$ min/veh

[ 1 hour = 60 minutes]

thus,

Average time spent by the vehicle = 2 min/veh

Hence,

Option (d) 2 min/veh

7 0

3 years ago

There is a dispute between the multiple parties storing financial transaction data on a blockchain over the validity of a transa

spayn [35]

Answer:

dgjkkkkkkkfdcvv

Explanation:

hjklllgfddsssssyjjjkkkk

p.s sorry

5 0

2 years ago

A body weighs 50 N and hangs from a spring with spring constant of 50 N/m. A dashpot is attached to the body. If the body is rai

lbvjy [14]

Answer:

a) 3.607 m

b) 1.5963 m

Explanation:

See that attached pictures for explanation.

3 0

2 years ago

The tolerance for a geometric can be easily identified by reading the _________.

baherus [9]

Answer:

Explanation:

4 0

3 years ago

Read 2 more answers

The steel bracket is used to connect the ends of two cables. if the allowable normal stress for the steel is sallow = 30 ksi, de

garri49 [273]

The largest tensile force that can be applied to the cables given a rod with diameter 1.5 is 2013.15lb

<h3>The static equilibrium is given as:</h3>

F = P (Normal force)

Formula for moment at section

M = P(4 + 1.5/2)

= 4.75p

Solve for the cross sectional area

Area = $\frac{\pi d^{2} }{4}$

d = 1.5

$\frac{\pi *1.5^{2} }{4}$

= 1.767 inches²

<h3>Solve for inertia</h3>

$\frac{\pi *0.75^4}{4}$

= 0.2485inches⁴

Solve for the tensile force from here

$\frac{F}{A} +\frac{Mc}{I}$

30x10³ = $\frac{P}{1.767} +\frac{4.75p*0.75}{0.2485} \\\\$

30000 = 14.902 p

divide through by 14.902

2013.15 = P

The largest tensile force that can be applied to the cables given a rod with diameter 1.5 is 2013.15lb

Read more on tensile force here: brainly.com/question/25748369

4 0

2 years ago