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juin [17]
4 years ago
12

Consider the biochemical pathway: A + E1 –> B + E2 –> C (Note that A, B, and C are molecules in the pathway, E1 is enzyme

1, and E2 is enzyme 2.) If enzyme 2 is inactive, which of the following compounds will accumulate?
Chemistry
1 answer:
MAVERICK [17]4 years ago
5 0

Answer:

The compound that will accumulate is B.

Explanation:

Enzymes in any biochemical process are the protein molecules that speed up the rate of the biological reaction. It lowers down the activation energy of the reactant molecules.

Since from the question:

<u>A + E1 –> B + E2 –> C</u>

Given that A, B and C are the molecules in the pathway and E1 and E2 are the enzymes.

<u>This means that A undergoes some biological reaction in which E1 is acting a catalyst to give B and which further undergoing another biological reaction to give C in the presence of enzyme E2.</u>

Since, E2 is inactive,

<u>A will form B but B will not be able to undergo further reaction and thus, C can not be formed.</u>

<u>Thus A is consumed and C is not formed. The compound that will accumulate is B.</u>

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What is the molarity of a potassium triiodide solution, KI3(aq), if 30.00 mL of the solution is required to completely react wit
vfiekz [6]

Answer:

The molarity is 0.203 M

Explanation:

Using the formula C(oxi) x V(oxi) / [C(red)  x  V(red)] = N(oxi) / N(red)

Where oxi and red means reducing agent and oxidising agent respectively.

C = Concentration, V = Volume and N = number of moles.

C(oxi) = 0.5 M

V(oxi) = mL

C(red) = ?

V(red) = 30mL

 Equation of reaction = 2K2S2O3 + KI3 = K2S4O6 + 3KI

so N(red) = 1 , N(oxi) = 2

from the equation above,

C(red) = 0.5 x 25 x 1 / (2 x 30)

          = 0.203 M.

3 0
3 years ago
A cylinder with a radius of 5.6 cm and a height of 10.7 cm has what volume? (You can look up the formula for the volume of a cyl
Keith_Richards [23]

Answer:

V=1054.2cm^{3}

Explanation:

1. First take the cylinder volume formula:

V=\pi.r^{2}.h

2. Then take the values for the radius and the height of the cylinder and replace them into the formula:

V=\pi*(5.6cm)^{2}*(10.7cm)

3. Solve the equation:

V=\pi*(31.36cm^{2})*(10.7cm)

V=\pi*335.5cm^{3}

V=1054.2cm^{3}

6 0
4 years ago
The reaction 2PH3(g)+As2(g)⇌2AsH3(g)+P2(g) has Kp=2.9×10−5 at 873 K. At the same temperature, what is Kp for each of the followi
slavikrds [6]

Answer:

Part A

Kp = 3.4 x 10⁴

Part B

Kp = 2.4 x 10⁻¹⁴

Part C

Kp = 1.2 x 10⁹

Explanation:

2PH₃(g) + As₂(g)  ⇌ 2 AsH₃(g) + P₂(g)  Kp = 2.9 x 10⁻⁵

Kp = [AsH₃]²[P₂]/[PH₃]²[As]  = 2.9 x 10⁻⁵

Part A

it is the inverse of the equilibrium given

Kp(A) = 1/ Kp = 1 / 2.9 x 10⁻⁵ = 3.4 x 10⁴

Part B

Is the equilibrium where the coefficients have been multiplied by 3,

Kp(B) = ( Kp )³ = ( 2.9 x 10⁻⁵ )³ = 2.4 x 10⁻¹⁴

Part C

This is the  reverse equilibrium multipled by 2.

Kp(C) = ( 1/Kp)² = ( 1/ 2.9 x 10⁻⁵ )² = 1.2 x 10⁹

8 0
3 years ago
Cobalt-60 is a strong gamma emitter that has a half- life of 5.26 yr. The co balt-60 in a radiotherapy unit must be replaced whe
Alenkasestr [34]

<u>Answer:</u> The sample of Cobalt-60 isotope must be replaced in January 2027

<u>Explanation:</u>

The equation used to calculate rate constant from given half life for first order kinetics:

t_{1/2}=\frac{0.693}{k}

where,

t_{1/2} = half life of the reaction = 5.26 years

Putting values in above equation, we get:

k=\frac{0.693}{5.26yrs}=0.132yrs^{-1}

Rate law expression for first order kinetics is given by the equation:

k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}

where,

k = rate constant = 0.132yr^{-1}

t = time taken for decay process = ? yr

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[A] = amount left after decay process =  (100 - 75) = 25 grams

Putting values in above equation, we get:

0.132=\frac{2.303}{t}\log\frac{100}{25}\\\\t=10.5yrs

The original sample was purchased in June 2016

As, June is the 6th month of the year, which means the time period will be 2016+\frac{6}{12}=2016.5

Adding the time in the original time period, we get:

2016.5+10.5=2027

Hence, the sample of Cobalt-60 isotope must be replaced in January 2027

3 0
3 years ago
42.7 L to mililiters
marin [14]
42700 milliliters would be the answer...

Hope this helps!
3 0
4 years ago
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