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juin [17]
3 years ago
12

Consider the biochemical pathway: A + E1 –> B + E2 –> C (Note that A, B, and C are molecules in the pathway, E1 is enzyme

1, and E2 is enzyme 2.) If enzyme 2 is inactive, which of the following compounds will accumulate?
Chemistry
1 answer:
MAVERICK [17]3 years ago
5 0

Answer:

The compound that will accumulate is B.

Explanation:

Enzymes in any biochemical process are the protein molecules that speed up the rate of the biological reaction. It lowers down the activation energy of the reactant molecules.

Since from the question:

<u>A + E1 –> B + E2 –> C</u>

Given that A, B and C are the molecules in the pathway and E1 and E2 are the enzymes.

<u>This means that A undergoes some biological reaction in which E1 is acting a catalyst to give B and which further undergoing another biological reaction to give C in the presence of enzyme E2.</u>

Since, E2 is inactive,

<u>A will form B but B will not be able to undergo further reaction and thus, C can not be formed.</u>

<u>Thus A is consumed and C is not formed. The compound that will accumulate is B.</u>

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The rate of disappearance of HBr in the gas phase reaction2HBr(g) → H2(g) + Br2(g)is 0.301 M s-1 at 150°C. The rate of appearanc
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