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juin [17]
4 years ago
12

Consider the biochemical pathway: A + E1 –> B + E2 –> C (Note that A, B, and C are molecules in the pathway, E1 is enzyme

1, and E2 is enzyme 2.) If enzyme 2 is inactive, which of the following compounds will accumulate?
Chemistry
1 answer:
MAVERICK [17]4 years ago
5 0

Answer:

The compound that will accumulate is B.

Explanation:

Enzymes in any biochemical process are the protein molecules that speed up the rate of the biological reaction. It lowers down the activation energy of the reactant molecules.

Since from the question:

<u>A + E1 –> B + E2 –> C</u>

Given that A, B and C are the molecules in the pathway and E1 and E2 are the enzymes.

<u>This means that A undergoes some biological reaction in which E1 is acting a catalyst to give B and which further undergoing another biological reaction to give C in the presence of enzyme E2.</u>

Since, E2 is inactive,

<u>A will form B but B will not be able to undergo further reaction and thus, C can not be formed.</u>

<u>Thus A is consumed and C is not formed. The compound that will accumulate is B.</u>

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steposvetlana [31]

Answer:

Answer : The correct answer for mass of KBr = 2.53 g

Given :

Molarity of KBr solution = 0.85 M

Volume of KBr solution = 25 mL

Converting volume from mL to L ( 1 L = 1000 mL )

Volume of solution = 25 mL * \frac{1 L }{1000mL}Volumeofsolution=25mL∗

1000mL

1L

Volume of solution = 0.025 L

Mass of KBr = ?

Mass of KBr can be calculated using following steps :

1) To find mole of Kbr :

Mole of KBr can be calculated using molarity .

Molarity : It is defined as mole of solute present in volume of solution in Liter .

It uses unit as M or \frac{mol}{L}

L

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It can be expressed as :

Molarity = \frac{mol of solute (mol)}{volume of solution (L)}Molarity=

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molofsolute(mol)

Plugging value of molarity and volume

0.85 \frac{mol}{L} = \frac{mol of Kbr}{0.025 L}0.85

L

mol

=

0.025L

molofKbr

Multiplying both side by 0.025 L

0.85 \frac{mol}{L} * 0.025 L = \frac{mole of KBr}{0.025 L} * 0.025 L0.85

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mol

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0.025L

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Mole of KBr = 0.02125

2) To find mass of Kbr :

Mass of Kbr can be calculated using mole . Mole can be expressed as :

Mole (mol) = \frac{mass (g) }{molar mass \frac{g}{mol} }Mole(mol)=

molarmass

mol

g

mass(g)

Mole of Kbr = 0.02125 mol

Molar mass of KBr = 119.00 \frac{g}{mol}

mol

g

Plugging values in mole formula

0.02125 mol = \frac{mass (g)}{119.00 \frac{g}{mol}}0.02125mol=

119.00

mol

g

mass(g)

Multiplying both side by 119.00 \frac{g}{mol}

mol

g

0.02125 mol * 119.00 \frac{g}{mol} = \frac{mass (g)}{119.00 \frac{g}{mol}} * 119.00\frac{g}{mol}0.02125mol∗119.00

mol

g

=

119.00

mol

g

mass(g)

∗119.00

mol

g

Mass of KBr = 2.53 g

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Anestetic [448]

Answer:

6.8 × 10⁻⁴ mol/L.atm

Explanation:

Step 1: Given data

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Step 2: Convert the partial pressure of nitrogen to atm

We will use the relationship 1 atm = 760 mmHg.

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We will use Henry's law.

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