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2 years ago

Determine the direction of bond polarity for each compound. Leave it blank for a nonpolar bond. Br−Br H−Cl F−CH3

Chemistry

1 answer:

NeX [460]2 years ago

8 0

Answer:

For H-Cl, the direction is towards the chlorine atom

For F-CH3, the direction is towards the flourine atom.

Explanation:

The dipole moment is a vector quantity. This implies that it has both magnitude and direction.

Thus, the direction of the dipole moment always points from the positive atom towards the negative atom.

This explains the fact that it points to chlorine in HCl and points to flourine in F-CH3

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What Does The Atomic Radius Change Down A Column Of The Periodic Table

CaHeK987 [17]

The atomic radius increases down a column (group) and decreases along a row

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2 years ago

HELP PLEASE!!!!!

Mashutka [201]

Answer:

National fire protection Association

Explanation:

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3 years ago

Hydrogen peroxide decomposes to water and oxygen at constant pressure by the following reaction: 2H2O2(l) → 2H2O(l) + O2(g) ΔH =

Mashcka [7]

<u>Answer:</u> The amount of heat released is -7.203 kJ

<u>Explanation:</u>

The given chemical equation follows:

$2H_2O_2(l)\rightarrow 2H_2O(l )+O_2(g);\Delta H=-196kJ$

To calculate the enthalpy change for 1 mole of the hydrogen peroxide, we use unitary method:

When 2 moles of hydrogen peroxide is reacted, the enthalpy of the reaction is -196 kJ

So, when 1 mole of hydrogen peroxide will react, the enthalpy of the reaction will be $\frac{-196}{2}\times 1=-98kJ$

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of hydrogen peroxide = 2.50 g

Molar mass of hydrogen peroxide = 34 g/mol

Putting values in above equation, we get:

$\text{Moles of hydrogen peroxide}=\frac{2.50g}{34g/mol}=0.0735mol$

To calculate the heat of the reaction, we use the equation:

$\Delta H_{rxn}=\frac{q}{n}$

where,

$q$ = amount of heat released

n = number of moles = 0.0735 moles

$\Delta H_{rxn}$ = enthalpy change of the reaction = -98 kJ/mol

Putting values in above equation, we get:

$-98kJ/mol=\frac{q}{0.0735mol}\\\\q=(-98kJ/mol\times 0.0735mol)=-7.203kJ$

Hence, the amount of heat released is -7.203 kJ

8 0

3 years ago

Let P and V represent the pressure and volume of the Xe(g) in the container in diagram 3. If a piston is used to reduce the volu

Reil [10]

Answer:

Explanation:

To solve this question, we can use Boyle's Law, which states that:

"For a fixed mass of an ideal gas kept at constant temperature, the pressure of the gas is inversely proportional to its volume"

Mathematically:

$p\propto \frac{1}{V}$

where

p is the pressure of the gas

V is its volume

The equation can be rewritten as

$p_1 V_1 = p_2 V_2$

where in this problem we have:

$p_1 = p$ is the initial pressure of the Xe(g) gas

$V_1=V$ is the initial volume of the Xe(g) gas

$V_2=\frac{V}{2}$ is the final volume of the Xe(g) gas

Solving for p2, we find the final pressure of the gas:

$p_2=\frac{p_1 V_1}{V_2}=\frac{pV}{V/2}=2p$

So, the final pressure is twice the initial pressure.

7 0

3 years ago

Krypton has a higher melting point than argon because of its:

dezoksy [38]

<h3>Answer:</h3>

Krypton has a higher melting point than argon because of its stronger dispersion forces.

<h3>Explanation:</h3>

Dispersion forces also known as London Dispersion forces are found in non polar compounds. These interactions take place in two steps.

Step 1: Instantaneous Dipole:

In non polar compounds the electron density on atom is symmetrical. When these symmetrical atoms approaches second symmetrical atom, a disturbance in electron densities occur due to repulsion between electrons. Due to repulsion the electrons density change there position and for a small period of time and instantaneous dipole is produced on an atom.

Step 2: Induced Dipole:

The dipole produced in step one when approaches another symmetrical atom, the partial positive part (low electron density site) attracts the electron from symmetrical atom and induces polarity in it. In this way the non polar atoms become polar and interacts with each other.

<h3>Factors Effecting Strength of Dispersion Forces:</h3>

i) Size of Atom / Molecule:

Greater the size of an atom greater will be the dispersion forces and vice versa.

ii) Shape of Molecules:

Greater the branching on molecule, weaker will be the dispersion forces and vice versa.

<h3>Conclusion:</h3>

As the size of Krypton is greater than Argon therefore, it will have stronger dispersion forces and will melt at higher temperature than Argon.

5 0

2 years ago