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3 years ago

Contrast the silica content of magma in quiet and explosive eruptions

1 answer:

3 0

Magma in quiet eruptions has a low content in silica , while in explosive eruptions, it has a high Content in silica. A volcano that erupts quietly has magma that is low in silica. Low-silica magma has low viscosity and flows easily. A volcano that erupts explosively has magma that is high in silica. High-silica magma has high viscosity, making it thick and sticky, thus it flows slowly.

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How to find the group number of f block elements

Vesnalui [34]

Answer:

I hope you understand please follow me please

8 0

3 years ago

When the submarine's density is equal to the density of the surrounding seawater, the submarine will maintain depth. If a 103200

GaryK [48]

Answer:

$2.023 m^3$ is the total displacement (volume) of the submarine.

Explanation:

Mass of water carried by submarine at 1000 ft depth = m = 2100 kg

The density of seawater at 1000 ft depth = d = $1033 kg/m^3$

Volume of the water displaced = V= ?

Total displacement of the submarine = Volume of the water displaced = V

$Density=\frac{Mass}{Volume}$

$V=\frac{m}{d}=\frac{2100 kg}{1033 kg/m^3}=2.023 m^3$

$2.023 m^3$ is the total displacement (volume) of the submarine.

6 0

2 years ago

Free-energy change, ΔG∘, is related to cell potential, E∘, by the equationΔG∘=−nFE∘where n is the number of moles of electrons t

mart [117]

Answer:

a) $\Delta G=372490 J$

b) $\Delta G=-568614 J$

Explanation:

a) The reaction:

$Mg(s) +Fe^{2+}(aq) \longrightarrow Mg^{2+}(aq) + Fe(s)$

The free-energy expression:

$\Delta G=-n*F*E$

$E=E_{red}-E_{ox]$

The element wich is reduced is the Fe and the one that oxidates is the Mg:

$-0.44V=E_{red}-(-2.37V)=1.93V$

The electrons transfered (n) in this reaction are 2, so:

$\Delta G=-2mol*96500 C/mol * 1.93 V$

$\Delta G=-372490 J$

b) If you have values of enthalpy and enthropy you can calculate the free-energy by:

$\Delta G=\Delta H - T* \Delta S$

with T in Kelvin

$\Delta G=-675 kJ*\frac{1000J}{kJ} - 298K*-357 J/K$

$\Delta G=-568614 J$

7 0

2 years ago

3 The volume of a gas is 50.0 mL at 20.0 K. What will be the new

Damm [24]

Answer:

C. 4.00 K

Explanation:

We can solve this using Charles's Law of the ideal gas. The law describes that when the pressure is constant, the volume will be directly proportional to the temperature. Note that the temperature here should only use the Kelvin unit. Before compressed, the volume of the gas is 50ml(V1) and the temperature is 20K (T1). After compressed the volume becomes 10ml(V2). The calculation will be:

V1 / T1= V2 / T2

50ml / 20K = 10ml / T2

T2= 10ml/ 50ml * 20K

T2= 4K

7 0

3 years ago

A 6.68-g aqueous solution of isopropyl alcohol contains 3.97 g of isopropyl alcohol. What is the mass percentage of isopropyl al

Sphinxa [80]

Answer : The mass percentage of isopropyl alcohol in the solution is, 59.4 %

Explanation :

To calculate the mass percentage of isopropyl alcohol in the solution, we use the equation:

$\text{Mass percent of isopropyl alcohol}=\frac{\text{Mass of isopropyl alcohol}}{\text{Mass of isopropyl alcohol solution}}\times 100$

Mass of isopropyl alcohol = 6.68 g

Mass of isopropyl alcohol solution = 3.97 g

Putting values in above equation, we get:

$\text{Mass percent of isopropyl alcohol}=\frac{3.97g}{6.68g}\times 100=59.4\%$

Thus, the mass percentage of isopropyl alcohol in the solution is, 59.4 %

6 0

3 years ago