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2 years ago

Contrast the silica content of magma in quiet and explosive eruptions

1 answer:

3 0

Magma in quiet eruptions has a low content in silica , while in explosive eruptions, it has a high Content in silica. A volcano that erupts quietly has magma that is low in silica. Low-silica magma has low viscosity and flows easily. A volcano that erupts explosively has magma that is high in silica. High-silica magma has high viscosity, making it thick and sticky, thus it flows slowly.

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Please,help me in question number 2 and 4.<br><img src="https://tex.z-dn.net/?f=2and4%20%5C%5C%20" id="TexFormula1" title="2and4

svetoff [14.1K]

I think it’s 890 I really don’t know

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3 years ago

Calculate the density of the items below. (D = M/V)<br> 1) M = 15g V = 5.0ml *

grin007 [14]

Answer:

<h3>The answer is 3.0 g/mL</h3>

Explanation:

The density of a substance can be found by using the formula

$density = \frac{mass}{volume} \\$

From the question

mass = 15 g

volume = 5 mL

We have

$density = \frac{15}{5} \\$

We have the final answer as

Hope this helps you

5 0

2 years ago

How do the properties of elements in the same column of the periodic table compare

Alik [6]

The columns of the periodic table, also referred to as "groups" contain elements with similar reactive properties, due to these elements having a similar configuration of electrons in their outer shell.

4 0

3 years ago

Which of the following will increase the number of collisions without changing the energy of reactant molecules?

natulia [17]

Answer:increasing the concentration of reactants

Explanation:

Collision is the phenomenon in which the reactant molecules come to nearest closness,as a result the reactants are converted into products.

Now the number of effective collision is directly proportional to the number of reactants added..

6 0

2 years ago

44.8% of a 250. mL acid solution is used in an experiment, what volume of acid (in mL) was used?

postnew [5]

Answer:

112 mL

Explanation:

The formula for percent by volume is

$\text{Percent by volume} = \dfrac{\text{Volume of solute}}{\text{Volume of solution}}\times 100 \, \%$

If you have 250 mL of a solution that is 44.8 % v/v,

$\begin{array}{rcl}44.8\, \% & = & \dfrac{\text{Volume of solute}}{\text{250 mL}}\times 100 \, \%\\\\44.8 \times \text{ 250 mL} & = & \text{Volume of solute} \times 100\\\text{Volume of solute} & = & \dfrac{44.8 \times 250\text{ mL}}{100}\\\\ & = & \textbf{112 mL}\\\end{array}$

7 0

3 years ago