Answer:
The answer to your question is below
Explanation:
A.
[H₃O⁺] = 2 x 10⁻¹⁴ M
pH = ?
Formula
pH = - log [H₃O⁺]
Substitution
pH = - log [2 x 10⁻¹⁴]
Result
pH = 13.7
B.
[H₃O⁺] = ?
pH = 3.12
Formula
pH = - log [H₃O⁺]
Substitution
3.12 = - log [H₃O⁺]
![10^{-3.12} = [H_{3} O^{+}]](https://tex.z-dn.net/?f=10%5E%7B-3.12%7D%20%3D%20%5BH_%7B3%7D%20O%5E%7B%2B%7D%5D)
Result
[H₃O⁺] = 7.59 M
Answer:
C.) HOCl Ka=3.5x10^-8
Explanation:
In order to a construct a buffer of pH= 7.0 we need to find the pKa values of all the acids given below
we Know that
pKa= -log(Ka)
therefore
A) pKa of HClO2 = -log(1.2 x 10^-2)
=1.9208
B) similarly PKa of HF= -log(7.2 x 1 0^-4)= 2.7644
C) pKa of HOCl= -log(3.5 x 1 0^-8)= 7.45
D) pKa of HCN = -log(4 x 1 0^-10)= 9.3979
If we consider the Henderson- Hasselbalch equation for the calculation of the pH of the buffer solution
The weak acid for making the buffer must have a pKa value near to the desired pH of the weak acid.
So, near to value, pH=7.0. , the only option is HOCl whose pKa value is 7.45.
Hence, HOCl will be chosen for buffer construction.
From the equation;
4 Al + 3 O2 = 2 Al2O3
The mole ratio of Oxygen is to Aluminium hydroxide is 3:2.
Therefore; moles of Al2O3 is
(0.5/3 )× 2 = 0.333 moles
Therefore; The moles of aluminium oxide will be 0.333 moles
Polair molecule, because the oxygen is slightly more negative than the two hydrogen atoms. Making water slightly negative. Due to the fact oxygen holds the to valence electrons more than the two hydrogen atoms do.
Answer:
Here's what I get.
Explanation:
- If your teachers don't ask for a specific type of formula, a condensed structural formula should be OK.
- If they ask specifically for a structural formula or a bond-line formula, that is what you must give.
Bottom line: ask your teachers in advance what they expect.
