Answer: 0.52 L of 15 M will be used to prepare this amount of 0.52 M base.
Explanation:
But on diluting the number of moles remain same and thus we can use molarity equation.
(to be prepared)
where,
=concentration of stock solution = 15 M
= volume of stock solution = ?
= concentration of solution to be prepared = 0.52 M
= volume of solution to be prepared = 15 L
Thus 0.52 L of 15 M will be used to prepare this amount of 0.52 M base
I believe it would be 7.731. x 10^5? That is if they want you to evaluate.
Answer: A and D, I believe
Explanation:
Answer:
Option D.
Explanation:
Some of the alpha particles Rutherford shot at the gold foil bounced back, some scattered; but the majority of them went right through. That meant there had to be some sort of positively charged subatomic particle in there that pulled them through, but it had to be at the center and couldn't take up a lot of room.