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3 years ago

QUICK PLEASE!!!

2 answers:

4 0

Answer. Answer: By adding more carbon dioxide to the atmosphere, the atmosphere becomes more "closed" to energy passing through it, absorbing more. Therefore, thermal energy that once would have been allowed to escape into space is instead absorbed by carbon dioxide and used to heat the Earth. So it’s B

gizmo_the_mogwai [7]3 years ago

4 0

As the amount of carbon dioxide increases the energy absorbed by the earths surface B-decreases

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Which of the following obtain their energy from the organisms they eat?

Zepler [3.9K]

The white-tailed deer. (D)

The rest are plants, which make their own energy from photosynthesis.

6 0

3 years ago

Read 2 more answers

The fourth type of Earth’s movement is galactic movement. What does the term galactic refer to?

Pavel [41]

Galactic is referring to the galaxy and cosmos! :)

8 0

4 years ago

Explain Charles law

kodGreya [7K]

"Charles Law" is the relationship between "volume-temperature" (V ∝ T).

<u>Explanation</u>:

Charles Law is basically volume-temperature relationship (V ∝ T). French scientist “Jacques Charles” in 1787 studied effect of temperature on the volume of gases at constant pressure, which described how gases manage to expand when heated. Law stated as “At constant pressure, the volume of a given "mass" of a gas decreases or increases by 1/273 of its volume at $0^{\circ} \mathrm{C}$ for each one degree rise or fall in temperature”. Formula derived from law is as follows: $\mathbf{V}_{\mathbf{t}}=\mathbf{V}_{0}[\mathbf{1}+\mathbf{t} / \mathbf{2} 7 \mathbf{3}]$ here ${V}_{0}$ is volume of given mass of a gas at $0^{\circ} \mathrm{C}$ , ${V}_{t}$ is its volume at any temperature $t^{\circ} \mathrm{C}$ . Application of Charles law is hot air balloons.

8 0

3 years ago

A saturated solution is made by dissolving 0.327 g of a polypeptide (a substance formed by joining together in a chainlike fashi

faust18 [17]

Answer: The approximate molecular mass of the polypeptide is 856 g/mol

Explanation:

To calculate the concentration of solute, we use the equation for osmotic pressure, which is:

$\pi=iMRT$

Or,

$\pi=i\times \frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution in L)}}\times RT$

where,

$\pi$ = osmotic pressure of the solution = 4.19 torr

i = Van't hoff factor = 1 (for non-electrolytes)

Mass of solute (polypeptide) = 0.327 g

Volume of solution = 1.70 L

R = Gas constant = $62.364\text{ L.torr }mol^{-1}K^{-1}$

T = temperature of the solution = $26^oC=[273+26]K=299K$

Putting values in above equation, we get:

$4.19torr=1\times \frac{0.327}{\text{Molar mass of solute}\times 1.70}\times 62.364\text{ L.mmHg }mol^{-1}K^{-1}\times 299K\\\\\text{molar mass of solute}=856g/mol$

Hence, the molar mass of the polypeptide is 856 g/mol

8 0

3 years ago

Consider the following reaction: 2{\rm{ N}}_2 {\rm{O(}}g)\; \rightarrow \;2{\rm{ N}}_2 (g)\; + \;{\rm{O}}_2 (g)

fredd [130]

Answer:

a. 5.9 × 10⁻³ M/s

b. 0.012 M/s

Explanation:

Let's consider the following reaction.

2 N₂O(g) → 2 N₂(g) + O₂(g)

Time (t): 12.0 s

Δn(O₂): 1.7 × 10⁻² mol

Volume (V): 0.240 L

We can find the average rate of the reaction over this time interval using the following expression.

r = Δn(O₂) / V × t

r = 1.7 × 10⁻² mol / 0.240 L × 12.0 s

r = 5.9 × 10⁻³ M/s

b. The molar ratio of N₂O to O₂ is 2:1. The rate of change of N₂O is:

5.9 × 10⁻³ mol O₂/L.s × (2 mol N₂O/1 mol O₂) = 0.012 M/s

4 0

3 years ago