Answer:
84 is the highest possible course average
Step-by-step explanation:
Total number of examinations = 5
Average = sum of scores in each examination/total number of examinations
Let the score for the last examination be x.
Average = (66+78+94+83+x)/5 = y
5y = 321+x
x = 5y -321
If y = 6, x = 5×6 -321 =-291.the student cannot score -291
If y = 80, x = 5×80 -321 =79.he can still score higher
If If y = 84, x = 5×84 -321 =99.This would be the highest possible course average after the last examination.
If y= 100
The average cannot be 100 as student cannot score 179(maximum score is 100)
y=2/3y-3
1. y = 2/3 (9)-3 multiply 9 and 2 =18/3
y=18/3-3 divide 18 and 3 =6
y=6-3 subt. 3
y=3
2. -11=2/3x - 3
-11+3 = 2/3 x add 3 to both sides to cancel -3
-8=2/3 x
(3/2)-8 = (2/3)3/2 x multiply both sides by reciprical of 2/3
-24/2 = x divide
-12=x
Answer:
Step-by-step explanation:
First order from smallest to largest.
70.8, 71.9, 72.1, 82.4, 85.3, 98.1.
Median is the middle number/s.
72.1+82.4/2 so The median is 77.25
Range is the largest number minus the smallest number.
85.3-70.8=14.5
Mode is the most repeated number.
Since there are no repeated numbers there is no mode.
Second question:
Again rearrage: 6, 9, 11, 14, 17
In order to make the median 10 you would have to add another 9 becasue
11+9/2 = 10
Third: remove 6 to make 12 the middle number
Fourth: add all numbers 90+x/6=20 so x has to be 30
When I finished the work my product is 1,817
Answer:
Step-by-step explanation:
Let x represent the initial weight of Porky the pig.
Porky the pig weighs 1,125 lbs less than Kobe the Cow. This means that the initial weight of Kobe the cow is
x + 1125
After each gains 50lbs. Kobe the Cow will weigh ten times as much as porky the pig. This means that
(x + 1125) + 50 = 10(x + 50)
x + 1125 + 50 = 10x + 500
10x - x = 1125 + 50 - 500
9x = 675
x = 675/9
x = 75
Porky's current weight is
75 + 50 = 125 lbs
Kobe's current weight is
(75 + 1125) + 50
= 1250 lbs
