1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
labwork [276]
3 years ago
6

The average bond length in C-C in benzene (C6H6) is between single and double bond lengths. This is due to which of the followin

g effect?
1. Due to its refractive index2. Due to the possession of resonance3. Due to its H atoms4. Due to the H-bonds
Chemistry
1 answer:
xeze [42]3 years ago
8 0

Answer:

2. Due to the possession of resonance

Explanation:

In the benzene ring, the electrons that results in the bonds between the carbon atoms are delocalized. That is, they do not belong to a specific carbon atom. It is this unique feature that enables them to have a bond length between single and double bond lengths.

This feature is as a result of resonance.

The correct option is 2.

You might be interested in
What is the most important role that water plays for living organisms?
Flauer [41]

Answer:

A. All organisms need water as energy source

8 0
3 years ago
Read 2 more answers
Describe the energy changes occurring of a glass of ice water and a glass of water
MatroZZZ [7]
I think it will stay the same. 
7 0
3 years ago
Which of the following statements about electronic configurations of atoms and mononuclear ions, and atomic orbital quantum numb
ruslelena [56]

Answer:

a. The electronic configuration of the hydride anion is 1s2. TRUE

b. The valence electronic configuration of strontium is 4d2.  FALSE

c. For a given value of l the number of possible values of ml is 2l + 1.  TRUE

d. Cu+ has the same electronic configuration as Ni.  TRUE

e. The magnetic quantum number is never larger than the principle quantum number (for a given orbital). TRUE

Explanation:

a. The electronic configuration of the hydride anion is 1s² is true since the hydriden anion is the hdrogen atom which has gained an electron and we will add that electron to the 1s¹ configuration of H.

b. The valence electronic configuration of strontium is 4d2 is false since Sr is an element of period 5 , therefore its valece electrons are in in period five and it has 2 electrons because Sr belongs to group 2.

c. For a given value of l the number of possible values of ml is 2l+1 is true since this number gives the magnetic orientation for the sublevel. Thus for s there is only one orientation, then ml = 2 (0 ) +1 . Por p with  l equal to 1 we have three possible orientations : 2(1) + 1 =3. The d and f sublevels have 10 and 14 orientations.

d. Cu⁺ has the the same electronic configuration as Ni is true since Cu, atomic number 29, has one more electron than its neighbor Ni with an atomic number of 28. If we remove one electron from copper we are gong to have the same 28 electrons niquel has in its neutral state.

e. The magnetic quantum number is never larger than the principal quantum  number for a given orbital is true since l, the magnetic quantum number can have values up to n-1, the principal quantum number.

4 0
3 years ago
OxYgen and hydrogen particles are kept in a container. Which of the following
Tema [17]

Answer:

Option D

Oxygen particles mix evenly with hydrogen particles.

Explanation:

Diffusion refers to the movement of gasses from a region of higher concentration to a region of lower concentration.

Diffusion occurs in gases because their particles are in a state of constant random motion.

Due to this continuous random motion, once the oxygen and the hydrogen are added to the container, they will begin to mix freely with each other until they fill up the entire volume of the container.

7 0
2 years ago
What is the limiting reactant in
MArishka [77]

Answer:

The limiting reactant is the K

Explanation:

This is the reaction:

2 K + F₂  → 2KF

2 moles of potassium react with 1 mol of fluorine

Let's determine the moles:

6.02x10²³ molecules are contained in 1 mol

10 molecules are contained in (10 . 1) / NA = 1.66x10⁻²³  moles

For 1 mol of flourine, we need 2 moles of K

If we have 1.66x10⁻²³  moles of Fl₂, we will need the double of K

For 2 moles of K, we need 1 mol of Fl₂

If we have 1.66x10⁻²³ moles of K, we will need the half of Fl₂

Then, the limiting reactant is the K

5 0
3 years ago
Other questions:
  • For any object in motion, distance is always _________ displacement
    5·1 answer
  • Using the round 2 fasttrack bond table (page 2), how is digby's "yield" calculated for their 10.0s2020 bond?
    7·1 answer
  • In h2o, the type of bond that holds one of the hydrogen atoms to the oxygen atom is a
    5·1 answer
  • What is the approximate volume of 19g of fluorine gas at a pressure of 4.0 atmospheres and a temperature of 127o C?
    7·1 answer
  • How would the addition of protons affect the concentration of CH3COOH? How would the addition of OH– affect the amount of CH3COO
    14·2 answers
  • Which is something that a PURE SUBSTANCE and a SOLUTION have in common?
    6·1 answer
  • Chapter 3 reactivity of metals mcq question and question and answer and important notes? ​
    10·1 answer
  • Which of the following is the term for the heaviness on something's surface that exerts a force over an area? a. force b. pressu
    9·2 answers
  • I need help with this pleas ASAP this is over due
    9·1 answer
  • 3. A reaction produces 14.2 grams of a product. The theoretical yield of that product
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!