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zhannawk [14.2K]
3 years ago
14

Help me i mark brain thing

Chemistry
1 answer:
o-na [289]3 years ago
5 0

Answer:

Becuase they can go through mountains and hills, they curve of of those.

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The diagram below shows three kettles with their powers and the time they take to boil 500cm3 of water. How much energy is trans
Bad White [126]

The energy transferred is given as the product of power and time. The 1.4 kW kettle with boiled water produces 378 kJ of energy.

<h3>What is energy?</h3>

Energy is the quantitative property that determines the work done by the body in the form of heat and light.

The image showing the kettles with time and power is attached below.

Given,

Power of the kettle = 1.4 kW

Time taken = 4.5 minutes

If power = energy ÷ time

Then, energy = power × time

= 1.4 × 0.075

= 0.105 KWh

Therefore, 0.105 kWh or 378KJ is the energy transferred.

Learn more about energy here:

brainly.com/question/16948772

#SPJ1

5 0
2 years ago
If 10 cubic centimeters of a liquid has a mass of
yulyashka [42]

Answer:

V = 10 m³

m = 70 grams

density = ....?

density = m/v

= 70/10

= 7 g/cm³ (B)

8 0
3 years ago
What is the oxidation number of neon
vredina [299]

Answer:

Electron Configuration and Oxidation States of Neon. Electron configuration of Neon is [He] 2s2 2p6. Possible oxidation states are 0. so the answer is 0.

Explanation:

7 0
4 years ago
Calculate the ph of the solution resulting from the addition of 85.0 ml of 0.35 m hcl to 30.0 ml of 0.40 m aniline (c6h5nh2). kb
stiv31 [10]

Answer:

pH = 0.81

Explanation:

HCl reacts with aniline, thus:

C₆H₅NH₂ + HCl → C₆H₅NH₃⁺ + Cl⁻

Moles of HCl are:

0.085L × (0.35mol HCl / L) = <em>0.02975mol HCl</em>

Moles of aniline are:

0.030L × (0.40mol HCl / L) = <em>0.012mol aniline</em>

Thus, after reaction, will remain:

0.02975mol - 0.012mol = <em>0.01775mol HCl</em>

Moles of HCl in solution are equal to moles of H⁺, thus, moles of H⁺ are: <em>0.01775mol H⁺</em>

As total volume is 85.0mL + 30.0mL = 115.0mL ≡ <em>0.115L</em>

0.01775mol / 0.115L = 0.1543M

pH of solution = -log[H⁺]

pH = -log 0.1543M

<em>pH = 0.81</em>

<em></em>

3 0
3 years ago
Read 2 more answers
What temperature will the water reach when 10.1 g CaO is dropped into a coffee cup containing 157 g H2O at 18.0°C if the followi
Zepler [3.9K]

Answer:

Final temperature attained by water = 34.6°C

Explanation:

The reaction of CaO and H₂O is an <em>exothermic reaction</em>. The equation of reaction is given below:

CaO + H₂O ----> Ca(OH)₂

The quantity of heat given off, ΔH°rxn = 64.8KJ/mol = 64800J/mol

Number of moles of CaO = mass/molar mass, where molar mass of Ca0 = 56g/mol, mass of CaO = 10.1g

Number of moles of CaO = 10.1g/56g/mol =0.179moles

Quantity of heat given off by 0.179 moles = 64800 *0.179 = 11599.2J/mol

Using the formula, <em>Quantity of heat, q = mass * specific heat capacity * temperature rise.</em>

mass of mixture = (10.1 + 157)g = 167.1g, Initial temperature = 18.0°C

Final temperature(T₂) - Initial temperature(T₁) = Temperature rise

11599.2J/mol = 167.1g * 4.18J/g·°C * ( T₂ - 18.0°C)

11599.2 = 698.478T₂ - 12572.604

11599.2 + 12572.604 = 698.478T₂

698.478T₂ = 24171.804

T₂ = 34.6°C

Therefore, final temperature attained by water = 34.6°C

6 0
4 years ago
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