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lyudmila [28]
3 years ago
14

Calculate the enthalpy of the reaction

Chemistry
1 answer:
Alik [6]3 years ago
5 0
We write the enthalpy change equation:

2ΔH_formation(NO) = ΔH_reaction + 2ΔH_formation(NO₂)
2(90.2) = ΔHr + 2(33.2)
ΔHr = 114 kJ/mol

The reaction releases 114 kJ/mol

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Pressure = 1002.7 / 14.696  = 68.2297 atm

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The conversion of T( °C) to T(K) is shown below:

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Applying the equation as:

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⇒n = 4.81 moles

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