How many ATOMS of boron are present in 3.61 grams of boron trifluoride ?

Chemistry

1 answer:

Delvig [45]3 years ago

3 0

Hi there!

$\large\boxed{3.203 * 10^{22} atoms}$

We can use the following conversions to solve:

Total mass --> amount of mols --> amount of atoms (Avogadro's number)

Begin by calculating the amount of boron trifluoride in 3.61 grams:

3.61 g * (1 mol BF₃ / 67.8 g) ≈ 0.0532 mol BF₃

Use avogadro's number to convert:

0.0532 mol * 6.02× 10²³atoms / 1 mol = 3.203 × 10²² atoms

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hope it helps...!!!