Combustion is a chemical reaction between a fuel and an oxidant, oxygen, to give off combustion products and heat. Complete combustion results when all of the fuel is consumed to form carbon dioxide and water, as in the case of a hydrocarbon fuel. Incomplete combustion results when insufficient oxygen reacts with the fuel, forming soot and carbon monoxide.
The complete combustion of propane proceeds through the following reaction:
+
-->
+
Combustion is an exothermic reaction, which means that it gives off heat as the reaction proceeds. For the complete combustion of propane, the heat of combustion is (-)2220 kJ/mole, where the minus sign indicates that the reaction is exothermic.
The molar mass of propane is 44.1 grams/mole. Using this value, the number of moles propane to be burned can be determined from the mass of propane given. Afterwards, this number of moles is multiplied by the heat of combustion to give the total heat produced from the reaction of the given mass of propane.
14.50 kg propane x <u> 1000 g </u> x <u> 1 mole propane </u> x <u> 2220 kJ </u>
1 kg 44.1 g 1 mole
=
729,931.97 kJ
Answer:
There are three atoms in the equation
Explanation:
2H2 + O2 = 2H2O
2mol. 1mol. 2mol
2mol reacts with 1mol
13mol reacts with x
x=<u>13mol</u><u> </u><u>×</u><u> </u><u>1mol</u>
<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u>2mol</u>
x= <u>13mol</u>
<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>2mol
x= 6.5mol of oxygen
Answer:
1. The correct option is;
c. maintains charge balance in the cell
2. The correct option is;
c. +3.272 V
Explanation:
The aqueous solution in a galvanic cell is the electrolyte which is a ionic solution containing that permits the transfer of ions between the separated compartment of the galvanic cell such that the overall system is electrically neutral
Therefore, the aqueous solution maintains the charge balance in the cell
2. Here we have;
B₂ + 2e⁻ → 2B⁻ Ecell = 0.662 V
A⁺ + 1e⁻ → A Ecell = -1.305 V
Hence for the overall reaction, we have;
2A + B₂ → 2AB gives;
(0.662) - 2×(-1.305) = +3.272 V.
Mass of C = 12g
mass of H = 1g
mass of O = 16g
mass of C2H5OH = 46g = 1 mole
1 mole of C2H5OH ------------ 46g
x moles of C2H5OH ----------- 230g
x = 5 moles of C2H5OH
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
mass of C = 12g
mass of H = 1g
mass of C2H4 = 28g = 1 mole
1 mole of C2H4 -------------- 28g
x moles of C2H4 ------------- 560g
x = 20 moles of C2H4
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
mass of S = 32g
mass of O = 16g
mass of SO2 = 64g = 1 mole
1 mole of SO2--------------------- 64g
x mole of SO2 -------------------- 0,64g
x = 0,01 moles of SO2