Answer:
Mass = 112.54 g
Explanation:
Given data:
Mass of copper = 18 g
How much copper(II) nitrate formed = ?
Solution:
Cu + 2AgNO₃ → Cu(NO₃)₂ + 2Ag
Number of moles of copper:
Number of moles = mass/ molar mass
Number of moles = 18 g/ 29 g/mol
Number of moles = 0.6 mol
Now we will compare the moles of Cu with Cu(NO₃)₂ .
Cu : Cu(NO₃)₂
1 : 1
0.6 : 0.6
Mass of Cu(NO₃)₂ :
Mass = number of moles × molar mass
Mass = 0.6 mol × 187.56 g/mol
Mass = 112.54 g
Answer:
The graph represents an endothermic reaction.
The products have more energy than the reactants.
80kJ
160kJ
80kJ
160kJ
<h3><u>Answer;</u></h3>
A) HNO3 and NO3^-
<h3><u>Explanation;</u></h3>
- <em><u>HNO3 is a strong acid and NO3 is its conjugate base, meaning it will not have any tendency to withdraw H+ from solution.</u></em>
- Buffers are often prepared by mixing a weak acid or base with a salt of that weak acid or base.
- The buffers resist changes in pH since they contain acids to neutralize OH- and a base to neutralize H+. Acid and base can not consume each other in neutralization reaction.
Answer:
Mole fraction O₂= 0.43
Explanation:
Mole fraction is the moles of gas/ total moles.
Let's determine the moles of each:
Moles O₂ → 15.1 g / 16 g/mol = 0.94
Moles N₂ → 8.19 g / 14 g/mol = 0.013
Moles H₂ → 2.46 / 2 g/mol = 1.23
Total moles = 2.183
Mole fraction O₂= 0.94 / 2.183 → 0.43