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3 years ago

Decrease £280 by 15%

Mathematics

1 answer:

aksik [14]3 years ago

7 0

Answer:

238

Step-by-step explanation:

280 times 0.85 = 238

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Using these coordinates, find the slope. (0, -6), (3, -2)

seropon [69]

Answer:

The slope between the points (0, -6) and (3, -2) will be:

$m=\frac{4}{3}$

Step-by-step explanation:

Given the points

(0, -6)

(3, -2)

The slope between the points (0, -6) and (3, -2) will be:

$\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}$

$\left(x_1,\:y_1\right)=\left(0,\:-6\right),\:\left(x_2,\:y_2\right)=\left(3,\:-2\right)$

$m=\frac{-2-\left(-6\right)}{3-0}$

$m=\frac{4}{3}$

Therefore, the slope between the points (0, -6) and (3, -2) will be:

$m=\frac{4}{3}$

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2 years ago

Which of the following expressions is equivalent to 13^(2)-3^(2)

Amiraneli [1.4K]

Answer:

160

Step-by-step explanation:

13² - 3² = 13 × 13 - 3 × 3 = 169 - 9 = 160

8 0

1 year ago

Un escalador sube 225m de altura. El asenso lo hizo en 3 etapas. En la primera subio un quinto en la, en la tercera un cuarto. ¿

kiruha [24]

Answer:

Segunda etapa= 123.75 metros

Step-by-step explanation:

Altura total= 225 metros

<u>En la primera estapa subió el 20% (un quinto):</u>

Primera etapa= 225*0.2= 45 metros

<u>En la tercera etapa subió 25% (un cuarto):</u>

Tercera etapa= 225*0.250 56.25 metros

Ahora debemos determinar cuánto subió en la segunda etapa:

Segunda etapa= altura total - total subido

Segunda etapa= 225 - (45 + 56.25)

Segunda etapa= 123.75 metros

6 0

2 years ago

Using the converse of Pythagorean Theorem and the law of sines and cosines solve the word problem.

Helga [31]

Answer:

It's the law of cosines

Step-by-step explanation:

law of cosines states that $c^{2} =a^{2} +b^{2} -2ab (cos(\alpha ))$

so we know that a = 7, b = 4, and alpha would be 135 degrees, so just plugging it in gets us 49+16-2*7*4*(-0.707) = 65 + 39.59 = 104.59

7 0

2 years ago

A product is now £50, the product was reduced by 20%, what was the original price

olga nikolaevna [1]

the original price is "x", or 100%.

but we know that if we reduce "x" by 20%, namely 100% - 20% = 80%, the 80% of "x" is really £50, what is "x" or the 100% anyway?

$\bf \begin{array}{ccll} amount&\%\\ \cline{1-2} x&100\\ 50&80 \end{array}\implies \cfrac{x}{50}=\cfrac{100}{80}\implies \cfrac{x}{50}=\cfrac{5}{4}\implies 4x=250 \\\\\\ x=\cfrac{250}{4}\implies x=62.5$

3 0

2 years ago