How are scientific discoveries used in engineering design?

4.71 A full-wave rectifier circuit with a 1-kΩ operates from a 120-V (rms) 60-Hz household supply through a 6-to-1 transformer h

brilliants [131]

Answer:

$V_{p (load)} = 28,3 V - 0,7 V = 27,6 V$

$V_{p (load)} = 27,6 V\\V_{avg} = 17,57 V$

The upper diode conduces in the odd half cycles. The lower diode conduces in the even half cycles.

$I_{avg} = \frac{V_{avg}}{R_{load}} = \frac{17,57 V}{1000 Ω} = 17,57 mA$

Explanation:

The peak voltage after the 6 to 1 step down is $V_{p} = \frac{120}{6} \sqrt{2} = 28,3V$ . Then, the peak voltage of the rectified output is $V_{p} - [tex]V_{avg} = \frac{2V_{p (load)} }{\pi} = \frac{55,2 V}{\pi } = 17,6 V$ V_{d}[/tex] and according to the statement, the diodes can be modeled to be $V_{d} = 0,7 V$ . Then, the peak voltage in the load is $V_{p (load)} = 28,3 V - 0,7 V = 27,6 V$ .

The upper diode conduces in the odd half cycles. The lower diode conduces in the even half cycles.

The average output voltage is calculated as:

$V_{p (load)} = 27,6 V\\V_{avg} = 17,57 V$

The average current in the load is calculated as:

$I_{avg} = \frac{V_{avg}}{R_{load}} = \frac{17,57 V}{1000 Ω} = 17,57 mA$

4 0

3 years ago

A part made from annealed AISI 1018 steel undergoes a 20 percent cold-work operation. Obtain the yield strength and ultimate str

Charra [1.4K]

Answer:

yield strength before cold work = 370 MPa

yield strength after cold work = 437.87 MPa

ultimate strength before cold work = 440 MPa

ultimate strength after cold work = 550 MPa

Explanation:

given data

AISI 1018 steel

cold work factor W = 20% = 0.20

to find out

yield strength and ultimate strength before and after the cold-work operation

solution

we know the properties of AISI 1018 steel is

yield strength σy = 370 MPa

ultimate tensile strength σu = 440 MPa

strength coefficient K = 600 MPa

strain hardness n = 0.21

so true strain is here ∈ = $ln\frac{1}{1-0.2}$ = 0.223

so

yield strength after cold is

yield strength = $K \varepsilon ^n$

yield strength = $600*0.223^{0.21)$

yield strength after cold work = 437.87 MPa

and

ultimate strength after cold work is

ultimate strength = $\frac{\sigma u}{1-W}$

ultimate strength = $\frac{440}{1-0.2}$

ultimate strength after cold work = 550 MPa

8 0

3 years ago

T

solniwko [45]

Answer:

Common Uses: Boxwood is well-suited for carving and turning, and the tree's diminutive size restricts it to smaller projects. Some common uses for Boxwood include: carvings, chess pieces, musical instruments (flutes, recorders, woodwinds, etc.), rulers, handles, turned objects, and other small specialty items.If you want a small, compact, low-growing shrub to form a hedge that serves as an accent or border along your walkway, fence line or planting beds, dwarf boxwood varieties are the best pick. The "Dwarf English" boxwood (Buxus sempervirens “Suffruticosa”) creates a border hedge approximately 1 to 2 feet in height.

Explanation:

3 0

3 years ago

Engineers need to be open-ended when dealing with their designs. Why?

melomori [17]

I think the answer would be A if its wrong I’m sorry

7 0

3 years ago

3.

Andreyy89

Answer:

7

Explanation:

5 + 2 = 7

4 0

2 years ago