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Gnoma [55]
3 years ago
7

Peter owns a hotel. He has found that when he charges $119 for a night’s stay, the average occupancy is 372 people. In addition,

Peter has found that with every $15 increase in the nightly cost, the hotel occupancy decreases by an average of 25. Write an expression to represent the nightly cost with x $15 price increases.
Mathematics
1 answer:
ozzi3 years ago
7 0
Without price increase,
Cost/night = $119
Average occupancy = 372
The revenue will be 119*372 = $44,268

For every $15 price increase, the occupancy decreases by 25.
Therefore with x price increases,
Cost/night = $119 + 15x
Occupancy = 372 - 25x
The revenue will be $(119 + 15x)*(372 - 25x)

Answer:
The nightly cost with x $15 price increases is $119 + 15x.
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Mkey [24]
In this case, since one equation is in the form of x=, substitution would be best for this problem.  Simply plug in 4y + 8 in place of x in the second equation, solve for y, then plug that value into the first equation to find x.
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12 + x/4 = 9<br> Simplify Plz need ASAP
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Answer: X = -12

Step-by-step explanation:  1)  12 + x/4 = 9

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What is the simplified form of (4x^2)^3
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Answer:

i guess the answer is 64x^5

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(4x^2)^3

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7 0
2 years ago
2) A pool is being filled with a hose. The equation y=12x represents the relationship between
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Answer:

D)  

Step-by-step explanation:

y = 12x.

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B) x = 10, so that y = 12(10) = 120.  It's on the line

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8 0
2 years ago
PLEASE HELP NEED THIS ANSWERED CORRECTLY
Helen [10]

f(3) = 1.9

Solution:

Given function:

$f(x)=\frac{14}{7+2 e^{-0.6 x}}

To find f(3):

Substitute x = 3 in the given function.

$f(3)=\frac{14}{7+2 e^{-0.6 (3)}}

$f(3)=\frac{14}{7+2 e^{-1.8}}

Let us first simplify 2e^{-1.8}.

Apply exponent rule: a^{-b}=\frac{1}{a^{b}}

$ 2e^{-1.8}=2\frac{1}{e^{1.8}}$

The value of e^{1.8}=6.04964. (using calculator)

$\frac{2}{e^{1.8}}=\frac{2}{6.04964}=0.33059

2e^{-1.8}=0.33059

Substitute this value in f(3).

$f(3)=\frac{14}{7+0.33059}

$f(3)=\frac{14}{7.33059}  

$f(3)=1.90980

f(3) = 1.9

Hence the value of f(3) is 1.9.

3 0
3 years ago
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