Answer:
i. 33
ii. 1488
iii. 65
Step-by-step explanation:
i. 4x² − 3y² + 5z²
Putting the values x=2, y=-1 and z=2
4(2)² − 3(-1)² + 5(2)²
4×4 − 3×(1)² + 5×(4)
(16) - (3×1) + (20)
16 - 3+ 20
36 - 3
33
ii. 3x³ − 2x(4yz+5x²)
Putting the values x=2, y=-1 and z=2
[3(2)³ − 2×2(4×(-1)×2 + 5×(2)²)]
[3(8)³ − 2×2(-8 + 5×4)]
[3 ×512 - 2×2(-8 +20)]
[1536 - 4(12)]
[1536 - 48]
1488
iii. 1−4x(yz+3xy)
Putting the values x=2, y=-1 and z=2
[1 - 4 × 2((-1)×2 + 3×2×(-1))]
[1- 8(-2 + (-6))]
[1- 8 (-2 -6)]
[1 - 8(-8)]
[1 +64]
65
Answer with explanation:
1.Mean of a Data set


2. Range = Maximum value in two conferences - Minimum value in two conference
= 12 - 0
=12
The mean number of wins for teams from the two conferences is 7.65.
The range in wins is 12.
Answer:

Step-by-step explanation:
Previous concepts
The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".
Solution to the problem
Let X the random variable of interest, on this case we now that:

The probability mass function for the Binomial distribution is given as:

Where (nCx) means combinatory and it's given by this formula:

The mean for the binomial distribution is given by:

And the variance is given by:

And the deviation is just the square root of the variance so we got:
