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3 years ago

Martin runs 100 meters in 15 seconds. What is the equation for d, the distance in meters that Martin covers per second.

Mathematics

1 answer:

Ivahew [28]3 years ago

6 0

Answer:i am not exactly sure but it should be three feet in each meter so mabey that should help you figure it out

Step-by-step explanation:

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A town has a population of 12000 and grows at 3.5% every year. What will be the population after 7 years, to the nearest whole n

Setler79 [48]

Answer:

15,267

Step-by-step explanation:

To solve this problem, lets use the exponential growth formula which is: $A = P(1+r)^t$

A = total amount

P = original amount

r = growth rate (decimal)

t = years

<u>Before we plug in the values, don't forget to change 3.5% to its decimal form.</u>

3.5% -> $\frac{3.5}{100}$ -> 0.035

Lets plug in the values:

$A=12,000(1+0.035)^7$

$A=15,267$

The population after 7 years will be 15,267.

8 0

3 years ago

emily has a bowl of M&M's for every 25 M&M's there are blue 5 M&M's. what percent of her M&M's are blue

KonstantinChe [14]

Answer:

twenty percent.

Step-by-step explanation:

25/5=5

100/5=20

8 0

3 years ago

Generate the first 5 terms of this sequence:

AURORKA [14]

<span>We are given f(1) = 0 and f(2) = 1. Going forward, the term is the sum of the two previous terms. f(3) = f(2) + f(1) = 0 + 1 = 1. f(4) = f(3) + f(2) = 1 + 1 = 2 f(5) = f(4) + f(3) = 2 + 1 = 3 This matches answer B.</span>

4 0

3 years ago

I need help on this if you know all the answers that would be great but if not I understand I am just struggling

tatyana61 [14]

Answer:

1. 8x+9

2. 3x + 11

3. 9x + 8

4. 11x+9

5. 6x

6. 10x+ 8

7. 7x+7

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

PLEASE HELP! I'll give 5 out of 5 stars, give thanks, and give as many points as I can.

Liula [17]

Answer:

$\boxed{\boxed{x=\dfrac{\pi}{3}\ \vee\ x=\pi\ \vee\ x=\dfrac{5\pi}{3}}}$

Step-by-step explanation:

$\cos(3x)=-1\iff3x=\pi+2k\pi\qquad k\in\mathbb{Z}\\\\\text{divide both sides by 3}\\\\x=\dfrac{\pi}{3}+\dfrac{2k\pi}{3}\\\\x\in[0,\ 2\pi)$

$\text{for}\ k=0\to x=\dfrac{\pi}{3}+\dfrac{2(0)\pi}{3}=\dfrac{\pi}{3}+0=\boxed{\dfrac{\pi}{3}}\in[0,\ 2\pi)\\\\\text{for}\ k=1\to x=\dfrac{\pi}{3}+\dfrac{2(1)\pi}{3}=\dfrac{\pi}{3}+\dfrac{2\pi}{3}=\dfrac{3\pi}{3}=\boxed{\pi}\in[0,\ 2\pi)\\\\\text{for}\ k=2\to x=\dfrac{\pi}{3}+\dfrac{2(2)\pi}{3}=\dfrac{\pi}{3}+\dfrac{4\pi}{3}=\boxed{\dfrac{5\pi}{3}}\in[0,\ 2\pi)\\\\\text{for}\ k=3\to x=\dfrac{\pi}{3}+\dfrac{2(3)\pi}{3}=\dfrac{\pi}{3}+\dfrac{6\pi}{3}=\dfrac{7\pi}{3}\notin[0,\ 2\po)$

7 0

4 years ago

Read 2 more answers