Question

How many moles of hf are needed to react with 0.380 mol of na2sio3?

Answer 1

Answer: 3.04 moles

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

The balanced chemical reaction is:

$8HF+Na_2SiO_3\rightarrow H_2SiF_6+2NaF+3H_2O$

According to stoichiometry:

1 mole of $Na_2SiO_3$ reacts with = 8 moles of $HF$

Thus 0.380 moles of $Na_2SiO_3$ reacts with = $\frac{8}{1}\times 0.380=3.04$ moles of $HF$

Thus 3.04 moles of $HF$ are needed to react with 0.380 mol of $Na_2SiO_3$

Answer 2

Hydrogen fluoride is a strong reactive towards $Na_{2}SiO_{3}$ which is a component of glass. Thus HF cannot keep in glass beaker or any glass made material. That is why HF is used to create mark on the glass in industrial process. The reaction between hydrogen fluoride (HF) and sodium silicate ($Na_{2}SiO_{3}$) is $Na_{2}SiO_{3}$+2HF=2NaF + Si$O_{2}$ + $H_{2}O$. Thus 1 mole of $Na_{2}SiO_{3}$ reacts with 2 moles of HF. So, 0.380 mol of $Na_{2}SiO_{3}$ will react with (0.380×2) = 0.76 mol of HF.