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Kruka [31]
3 years ago
14

Repulsion of electrons within two interacting molecules produces changes in electron distribution. This change in electron distr

ibution creates temporary dipole moments.Which of the following does this explain? Choose one or more: A. This explains how two noble gases' molecules can have an attractive force between them. B. This explains why ammonia and nitrogen gas exhibit an attractive force between them.C. This explains why long hydrocarbon chains have relatively high boiling points. D. This explains how the molecules hydrogen fluoride and methanol can exhibit uncharacteristically strong intermolecular forces. E. This explains why the dipole-dipole attractive force between dimethyl ether and acetone does not entirely account for the attractive force between these molecules.
Chemistry
1 answer:
ycow [4]3 years ago
6 0

Answer:

D

Explanation:

This explains how two noble gases molecules can have an attractive force between them.

This force is called as van dar Waals forces.

It plays a fundamental role in fields in as diverse as supramolecular chemistry structural biology .

If no other forces are present, the point at which the force becomes repulsive rather than attractive as two atoms near one another is called the van der Waals contact distance. This results from the electron clouds of two atoms unfavorably coming into contact.[1] It can be shown that van der Waals forces are of the same origin as the Casimir effect, arising from quantum interactions with the zero-point field.[2] The resulting van der Waals forces can be attractive or repulsive.[3] It is also sometimes used loosely as a synonym for the totality of intermolecular forces.[4] The term includes the force between permanent dipoles (Keesom force), the force between a permanent dipole and a corresponding induced dipole (Debye force), and the force between instantaneously induced dipoles

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Paul [167]
Solving this chemistry is a little bit hard because the question didn't give some important detailed. 
So first, there are a couple problems with your question. 
We will just need to know which direction will it proceed to reach equilibrium.
Your expression for Kc (and Qc ) for the reaction should be: 
Kc = [C] / [A] [B]^2 
You have not provided a value for Kc, so a value of Qc tells you absolutely nothing. Qc is only valuable in relation to a numerical value for Kc. If Qc = Kc, then the reaction is at equilibrium. If Q < K, the reaction will form more products to reach equilibrium, and if Q > Kc, the reaction will form more reactants.
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3 years ago
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weeeeeb [17]

Answer:

The answer is "\bold{CH_3COO^{-} \ (aq) + H^{+}\ (aq) \longrightarrow CH_3COOH \ (aq)}"

Explanation:

When HCI is added in the chemical equation it reacts with sodium acetate so, it will give the following chemical equation:

CH_3COONa\ (aq) + HCl\ (aq)\longrightarrow CH_3COOH\ (aq) + NaCl\ (aq)\\\\

 In this, the CH_3COOH is a weak acid so, it not completely dissociated.

CH_3COONa \ (aq) \ \ and \ NaCl were strong electrolytes they are completely dissociated.

The HCl is a strong acid so, it is completely dissociated So, the net ionic equation is:

CH_3COO^{-} \ (aq) + H^{+}\ (aq) \longrightarrow CH_3COOH \ (aq)

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Hey there.

By adding up all the "exponents," you'll get a number of 19. By looking at a periodic table, the element of such an atomic number is potassium or K.

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Explanation:

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