The many electron diamonds around the central carbon are 1689
Answer:
2.78x10⁻³ m
Explanation:
Nitrogen diffusion in the steel can be expressed using the following equation:
<u>Where:</u>
J: is the diffusion flux = 1.0x10⁻⁷ kgm⁻²s⁻¹
D: is the diffusion coefficient = 1.85x10⁻¹⁰ m²/s
C₁: is the concentration of nitrogen in the steel at the surface = 2 kg/m³
C₂: is the concentration of nitrogen at the distance x₂ = 0.5 kg/m³
x₁: is the distance at the surface = 0
x₂: is the distance to find
Hence, we have:
(1)
Solving equation (1) for x₂:
Therefore, the nitrogen will enter 2.78x10⁻³ m into the sheet.
I hope it helps you!
The solution would be like this for this specific problem:
<span>Given:
</span>66.0 g of carbon monoxide
reaction 2 C + O2 → 2 CO
<span>mol e= mass / molar mass <span>
<span>mole of 2CO = 66.0g / (12.011 15.999)g / mol </span>
mole of 2CO = 2.36 (CO and C has a 1:1 mole ratio)
mole of 2CO = 2.36 -> mole of 1 CO = 2.36 / 2 = 1.18
<span>We got 2 moles of C, thus 1.18 x 2 = 2.36
So, we 2.36 </span>moles of carbon are needed to produce 66.0 g of carbon monoxide in the </span>reaction
2 C + O2 → 2 CO.</span>
<span>To add, Carbon nonmetallic
and tetravalent, thus, making four electrons available to form covalent
chemical bonds. </span>