How many moles of calcium oxide will be produced when 1.6 moles of Iron(III)oxide reacts with calcium phosphate according to the
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Answer:
0.00725 M
Explanation:
Considering for
Mass = 5.66 g
Molar mass of = 80.043 g/mol
Moles = Mass taken / Molar mass
So,
<u>Moles = 5.66 / 80.043 moles = 0.0707 moles</u>
will dissociate as:
Thus 1 mole of yields 1 mole of ammonium ions. So,
<u>Ammonium ions furnished by = 1 × 0.0707 moles = 0.0707 moles</u>
Considering for
Mass = 4.42 g
Molar mass of = 149.09 g/mol
Moles = Mass taken / Molar mass
So,
Moles = 4.42 / 149.09 moles = 0.0296 moles
will dissociate as:
Thus 1 mole of yields 3 moles of ammonium ions. So,
<u>Ammonium ions furnished by = 3 × 0.0296 moles = 0.0888 moles</u>
<u>Total moles of the ammonium ions = 0.0707 + 0.0888 moles = 0.1595 moles</u>
Given that:
Volume = 22.0 L
So, Molarity of the is:
<u>Molarity = Moles / Volume = 0.1595 / 22 M = 0.00725 M</u>