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anastassius [24]
3 years ago
12

How many moles of calcium oxide will be produced when 1.6 moles of Iron(III)oxide reacts with calcium phosphate according to the

following (unbalanced) reaction
Chemistry
1 answer:
koban [17]3 years ago
4 0

Answer:


4.8 mol


Step-by-step explanation:


The balanced equation is


Fe₂O₃ + Ca₃(PO₄)₂ ⟶2FePO₄ + 3CaO


You want to convert moles of Fe₂O₃ to moles of CaO.


The molar ratio is 3 mol CaO:1 mol Fe₂O₃.


Moles of CaO = 1.6 mol Fe₂O₃ × (3 mol CaO/1 mol Fe₂O₃)


Moles of CaO = 4.8 mol CaO


The reaction will produce 4.8 mol of CaO.

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How many moles of oxygen are needed to react with 87 grams of aluminum
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Answer:

2.4 moles of oxygen are needed to react with 87 g of aluminium.

Explanation:

Chemical equation:

4Al(s)  + 3O₂(l)   → 2AlO₃(s)

Given data:

Mass of aluminium = 87 g

Moles of oxygen needed = ?

Solution:

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Now we will compare the moles of aluminium with oxygen.

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                               4          :         3

                               3.2       :         3/4×3.2 = 2.4 mol

2.4 moles of oxygen are needed to react with 87 g of aluminium.

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