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Harlamova29_29 [7]
3 years ago
5

A beaker contains a 25 mL solution of an unknown monoprotic acid that reacts in a 1:1 stochiometric ratio with NaOH. Titrate the

solution with NaOH to determine the concentration of the acid.
Perform a titration by setting the concentration of the NaOH solution and adding it to the acid solution using the different.
Chemistry
1 answer:
Luden [163]3 years ago
8 0

Answer:

concentration of HCL = 4.56 g/dm3

Explanation:

If the titrant and analyte have a 1:1 mole ratio, the formula is molarity (M) of the acid x volume (V) of the acid = molarity (M) of the base x volume (V) of the base. (Molarity is the concentration of a solution expressed as the number of moles of solute per litre of solution.)

Step 1: Calculate the amount of sodium hydroxide in moles

Volume of sodium hydroxide solution = 25.0 ÷ 1,000 = 0.0250 dm3

Rearrange:

Concentration in mol/dm3 = \frac{\textup{amount~of~solute~in~mol}}{\textup{volume~in~dm}^3}

Amount of solutein mol = concentration in mol/dm3 × volume in dm3

Amount of sodium hydroxide = 0.100 × 0.0250

= 0.00250 mol

Step 2: Find the amount of hydrochloric acid in moles

The balanced equation is: NaOH(aq) + HCl(aq) → NaCl(aq) + H2O(l)

So the mole ratio NaOH:HCl is 1:1

Therefore 0.00250 mol of NaOH reacts with 0.00250 mol of HCl

Step 3: Calculate the concentration of hydrochloric acid in mol/dm3

Volume of hydrochloric acid = 20.00 ÷ 1000 = 0.0200 dm3

Concentration in mol/dm3 = \frac{\textup{amount~of~solute~in~mol}}{\textup{volume~in~dm}^3}

Concentration in mol/dm3 = \frac{\textup{0.00250}}{\textup{0.0200}}

= 0.125 mol/dm3

Step 4: Calculate the concentration of hydrochloric acid in g/dm3

Relative formula mass of HCl = 1 + 35.5 = 36.5

Mass = relative formula mass × amount

Mass of HCl = 36.5 × 0.125

= 4.56 g

So concentration = 4.56 g/dm3

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Data was collected by students in an acid base titration lab. They used 1.63 M Ca(OH)2(AQ)
jenyasd209 [6]

Answer:

3.8 M

Explanation:

Volume of acid used VA= 57.0 - 37.5 = 19.5 ml

Volume of base used VB= 67.8 - 45.0 = 22.8 ml

Equation of the reaction

2HNO3(aq) + Ca(OH)2(aq) --------> Ca(NO3)2(aq) + 2H2O(l)

Number of moles of acid NA= 2

Number of moles of base NB= 1

Concentration of acid CA= ???

Concentration of base CB= 1.63 M

CAVA/CBVB = NA/NB

CAVANB = CBVBNA

CA= CBVBNA/VANB

CA= 1.63 × 22.8 × 2/ 19.5 × 1

CA= 3.8 M

HENCE THE MOLARITY OF THE ACID IS 3.8 M.

6 0
3 years ago
I need an answer and explanation pls
OverLord2011 [107]

Answer:

Cl2 + 2NaBr --> 2NaCl + Br2

Explanation:

This is a single displacement reaction where one side of the ionic compound switches with the other.

So, Cl2 + NaBr ---> NaCl + Br2

This isolates the Bromine and puts the Chlorine in it's place.

Then, balance out the equation like so and you should get

Cl2 + 2NaBr --> 2NaCl + Br2

8 0
3 years ago
The number of particles in one mole of a substance is:
spayn [35]
Avogadros number is the answer
3 0
3 years ago
2. When two forces act on an object in opposite directions, you calculate the net
exis [7]

When two forces act on an object in opposite directions, the net  force can be calculated by subtracting the two forces.

<u>Explanation:</u>

  • The net/final force by subtracting the two given opposite forces as asked in the above question.

For example: If you keep a bottle on the table, the downward force subtracted from the upward force will be equal to the net force.

  • If the net force equals zero then the objects will be balanced, otherwise unbalanced.

For example: In the tug of war when two forces are of different units the force with the greater strength will have an advantage, like if the team on the right is stronger than that of left than the rope will move towards the right.

5 0
3 years ago
2. A flask and stopper have a mass of 110.525 g. A 50.0-mL sample of gasoline is transferred to the flask, and the flask, stoppe
Dominik [7]

Answer:

  0.690 g/mL

Explanation:

Density is the ratio of mass to volume:

  gasoline mass = (flask+gas mass) - (flask mass) = 145.028 g -110.525 g

  gasoline mass = 34.503 g

Density = (gas mass)/(gas volume) = (34.503 g)/(50.0 mL)

Density = 0.690 g/mL

_____

The least-precise number in this calculation is the sample volume, which has 3 significant figures. Thus, the answer is good only to 3 significant figures.

8 0
3 years ago
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