40.1g of nitrogen gas is produced.
The equation given is
2 NH₃ + 3 CuO →3 Cu + N₂ + 3 H₂O
This equation is already balanced.
When 3 moles of CuO are consumed, 1 mole of nitrogen gas is produced.
We get 1 mole of nitrogen from 3 moles of copper oxide.
We need to find the number of moles of nitrogen gas produced when 4.3 moles of copper oxide are consumed.
4.3/3 x 1 = 1.433 mols
- 1.433 mols of nitrogen gas are produced
- The molar mass of nitrogen gas is 14+14 = 28g
- The amount of nitrogen gas produced in grams is 28x1.433 = 40.1g
40.1g of nitrogen gas can be made when 4.3 moles of CuO are consumed.
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Answer:
0.99 pounds
2,000 oz
0.423 cups
Explanation:
In order to convert this units we need to look up their equivalences.
1 g equals 0,0022 pounds approximately
Then we need to cross-multiply:
450 g equals 0.99 pounds approximately
We can do the same calculation for the other 2 ingredients
1 g equals 16 oz
Then (125 g x 16 oz) / 1 oz = 2,000 oz (or 500 4 oz)
1 cup equals 236.59 ml
Then (100 ml x 1 cup)/ 236.59 = 0.423 cups
Answer:
True
Explanation:
Sometimes you will need to convert from grams to moles, or moles to grams
Answer;
4.5 m³
Solution:
The statement says that two blocks are present on a lid of a container with volume of 9 m³. The mass of lid is equal to the mass of two blocks. It means that initially there are four blocks (or four atm pressure) upon 9 m³ volume.
After that four more blocks are placed on the lid. Means the pressure is increased from 4 atm to 8 atm (2 atm of lid, 2 atm of old blocks, 4 atm of new four blocks).
So, Data generated is,
P₁ = 4 atm
V₁ = 9 m³
P₂ = 8 atm
V₂ = ?
According to Boyle's Law,
P₁ V₁ = P₂ V₂
Solving for V₂,
V₂ = P₁ V₁ / P₂
Putting values,
V₂ = (4 atm × 9 m³) ÷ 8 atm
V₂ = 4.5 m³
