1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
larisa86 [58]
3 years ago
14

Draw the major monobromination product formed by heating the following alkane with bromine.

Chemistry
1 answer:
yawa3891 [41]3 years ago
8 0
A monobromination reaction of an alkane involves an alkane and bromine. The position of the hydrogen atom that will be substituted by the bromine free radical will depend on the order of the alkane. The bromine will attach to the carbon that has the most substituents.
You might be interested in
SOME ONE HELP ME ON THIS WEBSITE
Sergio039 [100]
Every cell has a nucleus unless it is RNA which is involved with DNA movement
4 0
3 years ago
I need help pleasee
Readme [11.4K]

Answer:

Explanation:

6. Where on the graph does adding heat energy NOT raise the temperature?

What is the heat energy DOING if it's not raising the temperature?  :its being compressed I believe its vaporizing

7. What is temperature A called?  Freezing

8. What is temperature B called? Vaporizing

4 0
3 years ago
What is the mass percent of nitrogen in ammonium carbonate, (NH4)2CO3?
Margaret [11]

In order for you to calculate for the mass of ammonium carbonate, you need to know the molar mass of it and the nitrogen atoms in the compound. Ammonium carbonate has a molar mass of 96.08 grams per mole. There are two nitrogen atoms in ammonium carbonate which is equal to 28.02 grams per mole. Divide the molar mass of nitrogen to the ammonium carbonate, 28.02/96.08 x 100, we get 29.16wt% nitrogen.

6 0
3 years ago
The reduction of ketone groups, such as those present on coq, produces alcohols. in contrast, oxidation of aldehydes produces wh
nevsk [136]

On oxidation of aldehydes produces carboxylic acid functional group.

The product of oxidation of aldehydes depends upon whether the reaction occur in acidic medium or alkaline condition.

If oxidation of aldehydes occurs under acidic condition the product is carboxylic acid but if oxidation of aldehydes occurs under alkaline condition then reduce as well as oxidized product obtained which is known as disproportional product.

The  oxidation of aldehydes occur through potassium dichromate, potassium permanganate or many more. The oxidation of aldehydes in the presence of base is known as cannizzaro's reaction.

learn about oxidation

brainly.com/question/16976470

#SPJ4

7 0
2 years ago
Why is blue so rare in nature?​
vladimir1956 [14]

Answer:

Explanation:

For a flower to appear blue, "it needs to be able to produce a molecule that can absorb very small amounts of energy," in order to absorb the red part of the spectrum, Kupferschmidt said.

7 0
2 years ago
Read 2 more answers
Other questions:
  • If you have 0.56 moles of an ideal gas at 87c and a pressure of 569 torr, what volume will the gas take up
    9·1 answer
  • Which of the following is not an example of a polymer?
    15·2 answers
  • If we mix 25 grans if sodium oxide with a large amount of potassium chloride, how many grams of sodium chloride should be produc
    15·1 answer
  • what are we/what has someone did to prevent/lessen the negative side effects of aluminium extraction?
    14·1 answer
  • Helpppppppppppppp!!!!!!!
    15·1 answer
  • What would you need to do to calculate the molality of 10 mol of NaCl in 200
    14·1 answer
  • intrusive igneous rock forms when the cooling of magma takes place fast on the top of the Earth's surface. A. True B. False
    6·2 answers
  • Which statement describes the charging method shown?
    6·2 answers
  • How does the moon affect the Earth's tides?
    6·2 answers
  • for number less than 0.1, such as 0.06, the zeros to the right of the decimal point but before the first nonzero digit
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!