Question

80.0 mL of oxygen gas was collected when the temperature was

Answer 1

Answer:

89.3 mL

Explanation:

First we convert 20.0 °C and 54.0 °C to K:

• 20.0 °C + 273.16 = 293.16 K

• 54.0 °C + 273.16 = 327.16 K

With the absolute temperatures we can solve this problem by using Charles' law:

• T₁V₂=T₂V₁

Where in this case:

• T₁ = 293.16 K

• V₂ = ?

• T₂ = 327.16 K

• V₁ = 80.0 mL

We input the data:

• 293.16 K * V₂ = 327.16 K * 80.0 mL

And solve for V₂:

• V₂ = 89.3 mL