Question

A sample of three mixed gases is at 632.0 mmhg. if the partial pressure of co2 is 124.3 mmhg and the partial pressure of n2 is 461.9 mmhg, what is the partial pressure of o2?

Answer 1

Answer:

45.8 mmhg

Explanation:

According to Dalton's law of partial pressure, the total pressure of a gas mixture is the sum of the partial pressure of the individual gases that make up the mixture.

Mathematically, the law can be expressed as:

$P_{total} = P_1 + P_2 + ........ + P_n$

In this case,

$P_{total}$ = 632.0 mmhg,

$P_{co2}$ = 124.3 mmhg

$P_{N2}$ = 461.9

$P_{O2}$ = ?

$P_{total} = P_{co2} + P_{N2} + P_{O2}$

                632.0 = 124.3 + 461.9 + $P_{O2}$

$P_{O2}$ = 632.0 - + 124.3 + 461.9

                              = 45.8 mmhg

The partial pressure of O2 is 45.8 mmhg

Answer 2

According to Dalton's Law of Partial pressures, the sum of the partial pressures of the individuals gas molecules that occupy a specific volume allows us to find the total pressure or find one of the partial pressures if the total pressure is known.

Partial pressure O2 = 632 - 124.3 - 461.9 = 45.8 mm Hg.