When we have Kw = 1.2x10^-15
and according to Kw formula:
Kw = [OH-] [H+]
by substitution:
1.2x10^-15 = [OH-][H+]
when the solution is neutral that means:
[OH-] = [H+]
∴1.2X10^-15 = X^2
∴X = 3.46 x 10^-8
∴[OH-] = [H+] = 3.46x10^-8
Answer:
https://courses.lumenlearning.com/boundless-biology/chapter/atoms-isotopes-ions-and-molecules/
Explanation:
<u>Answer:</u> The number of moles of 
is 0.05 moles.
<u>Explanation:</u>
To calculate the molarity of solution, we use the equation:
We are given:
Molarity of solution = 0.10 mol/L
Volume of solution = 1 L
Putting values in above equation, we get:
The chemical reaction for the ionization of sodium sulfate follows the equation:
By Stoichiometry of the reaction:
2 moles of sodium ions are produced by 1 mole of sodium sulfate
So, 0.10 moles of sodium ions will be produced by = 
of sodium sulfate.
Hence, the number of moles of is 0.05 moles.
Answer:
The correct answer is 4.58 grams.
Explanation:
Based on the Faraday's law of electrolysis, at the time of electrolysis, the amount of deposited substance is directly equivalent to the concentration of the flow of charge all through the solution. If current, I, is passed for time, t, seconds and w is the concentration of the substance deposited, then w is directly proportional to I*t or w = zIt (Here z refers to the electrochemical equivalent or the amount deposited when 1 C is passed).
For the reaction, n * 96500 C = molar mass
1C = molar mass/n*96500 = Equivalent wt / 96500
w = Equivalent wt / 96500 * I * t
In the given reaction,
Pb + PbO2 + 2HSO4- + 2H+ → 2PbSO4 + 2H2O, n = 2, the current or I drawn is 350 A, for time, t 12.2 seconds.
Now putting the values in the equation we get,
w = 207.19 / 2 * 96500 * 350 * 12.2 ( The molecular weight of Pb is 207.19 and the equivalent weight of Pb is 207.19 / 2)
w = 4.58 gm.
J. Hope this helps you!