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Soloha48 [4]
3 years ago
9

Answers please, I will give brainliest

Chemistry
1 answer:
Andrei [34K]3 years ago
7 0

Bellow you may find the names and structure of the poliatomic ions.

Explanation:

sulfate SO₄²⁻

nitrate NO₃⁻

perphosphate PO₅²⁻

hypoiodite IO⁻

chlorite ClO₂⁻

phosphite PO₃³⁻

percarbonate H₃CO₆²⁻

bromate  BrO₃⁻

hyposulfite SO₂²⁻

permanganate MnO₄⁻

carbonite CO₂²⁻

CO₃²⁻ carbonate

MnO₃⁻ manganate

SO₅²⁻  persulfate

BrO₂¹⁻ bromite

CO₄²⁻ percarbonate

PO₅³⁻ perphosphate

ClO¹⁻ hypochlorite

IO₂¹⁻ iodate

PO₄³⁻ phosphate

NO₂¹⁻ nitrite

SO₄²⁻ sulfate

Learn more about:

polyatomic ions

brainly.com/question/4191889

brainly.com/question/13659069

#learnwithBrainly

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If a sample of a gas occupies 5.22 L at 235 oC, what will its volume be at 75 oC if the pressure remains the same?
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Answer:

1618.2

Explanation:

235+75=310×75=1618.2

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Calculate the percent by mass of 10 grams of calcium hydroxide mixed in 65 grams of water
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Answer:

13.3 %

Explanation:

Percent by mass indicates the mass of solute in 100g of solution.

We must know the solution's mass:

Solution's mass = Solute mass + solvent mass

Solution's mass = 10 g + 65 g = 75 g

Percent by mass = (10 g / 75 g).100 = 13.3 %

Otherwise, we can make a rule of three:

In 75 g of solution we have 10 g of solute

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A sample of glucose ( C6H12O6 ) of mass 8.44 grams is dissolved in 2.11 kg water. What is the freezing point of this solution? T
zhuklara [117]

Answer:

- 0.0413°C ≅ - 0.041°C (nearest thousands).

Explanation:

  • Adding solute to water causes the depression of the freezing point.

  • We have the relation:

<em>ΔTf = Kf.m,</em>

Where,

ΔTf is the change in the freezing point.

Kf is the freezing point depression constant (Kf = 1.86 °C/m).

m is the molality of the solution.

<em>Molality is the no. of moles of solute per kg of the solution.</em>

  • <em>no. of moles of solute (glucose) = mass/molar mass</em> = (8.44 g)/(180.156 g/mol) = <em>0.04685 mol.</em>

<em>∴ molality (m) = no. of moles of solute/kg of solvent</em> = (0.04685 mol)/(2.11 kg) = <em>0.0222 m.</em>

∴ ΔTf = Kf.m = (1.86 °C/m)(0.0222 m) = 0.0413°C.

<em>∴ The freezing point of the solution = the freezing point of water - ΔTf </em>= 0.0°C - 0.0413°C = <em>- 0.0413°C ≅ - 0.041°C (nearest thousands).</em>

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Meaning of carbon cycle​
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