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frez [133]
3 years ago
15

The specific heat of gold is 0.031 calories/gram°C. If 10.0 grams of gold were heated and the temperature of the sample changed

by 20.0°C, how many calories of heat energy were absorbed by the sample?
Chemistry
2 answers:
Vitek1552 [10]3 years ago
6 0

Answer : The heat energy absorbed by the sample was 6.2 calories.

Explanation :

Formula used :

Q=m\times c\times \Delta T

where,

Q = heat absorbed = ?

m = mass of gold = 10.0 g

c = specific heat of gold = 0.031cal/g^oC

\Delta T = change in temperature  = 20.0^oC

Now put all the given value in the above formula, we get:

Q=10.0g\times 0.031cal/g^oC\times 20.0^oC

Q=6.2cal

Therefore, the heat energy absorbed by the sample was 6.2 calories.

Phoenix [80]3 years ago
3 0
10 grams of gold would have a specific heat of 0.31 calories ie 10 x 0.031 and if heated up by 20.0 degrees centigrade then 20.0 x 0.31 would be a 6.2 calorie increase in heat. In other words, the specific heat means that it is the calories produced in the gram of gold by a 1 degree rise in degrees centigrade.
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What changes would occur at a molecular level if a liquid is placed in cool conditions?
Dafna1 [17]

Answer: Option (C) is the correct answer.

Explanation:

Movement of particles in a substance is responsible for change in state of the substance or matter.

This means that more is the motion of particles more will be their kinetic energy.  

Also, kinetic energy is directly proportional to temperature.  

                     K.E = \frac{3}{2}kT  

So, less is the temperature of an object or substance less will be be the motion of its particles. Therefore, molecules will come closer to each other and state of substance will change from liquid to solid.

Thus, we can conclude that the motion of the molecules would decrease at a molecular level if a liquid is placed in cool conditions.

6 0
2 years ago
Consider the following intermediate chemical equations. When you form the final chemical equation, what should you do with CO? C
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Answer:

Cancel out CO because it appears as a reactant in one intermediate reaction and a product in the other intermediate reaction.

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5 0
3 years ago
A compound is formed when 12.2 g Mg combines completely with 5.16 g N. What is the percent composition of this compound? Please
STALIN [3.7K]
3Mg + N₂= Mg₃N₂
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</span>n(N₂)=5,16g÷28g/mol=0,18mol
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3 years ago
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8 0
2 years ago
Help me please :3 :3 :3 ;3
Alona [7]
I think the answer is C.
8 0
3 years ago
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