Answer:
2.down is hypotheses and 23.across is experiment
Explanation:
akechis pancakes
<u>Answer:</u> The cross-sectional area of the cylindrical rod is 
<u>Explanation:</u>
We are given a cylindrical rod whose cross-sectional area will be in the form of circle.
To calculate the area of circle, we use the equation:

where,
r = radius of the rod =
(Conversion factor: 1 m = 1000 mm)
Putting values in above equation, we get:

Hence, the cross-sectional area of the cylindrical rod is 
In Chemistry, a reactivity series of metals , also known as the activity series refers to the arrangement of metals in the descending order based upon their reactivity .
<u>Salient Features</u> :-
- The metal at the top of the reactivity series are powerful reducing agents since they are easily oxidized.
- The reducing ability of metals grows weaker while traversing down the series.
- The electro-positivity of metals also reduces while moving down the reactivity series.
- Metals that are placed higher on the reactivity series have the ability to displace metals that are placed lower in the series.
<u>The metal reactivity series is given below</u> :-
To access the reactivity of metal , from the given reactivity series identify any of the metal and locate the reactivity based upon the choice of reactivity. The metal at the top (Potassium) is most reactive and the metal at the bottom (Platinum) is the least reactive.
To learn more about metal reactivity series visit -
brainly.com/question/16072297
Answer:
I think is c: Product of mixing acids and bases
Tell if Im right
<u>Answer:</u> The pressure that must be applied to the apparatus is 0.239 atm
<u>Explanation:</u>
To calculate the osmotic pressure, we use the equation for osmotic pressure, which is:

or,

where,
= osmotic pressure of the solution
i = Van't hoff factor = 1 (for non-electrolytes)
= mass of sucrose = 3.40 g
= molar mass of sucrose = 342.3 g/mol
= Volume of solution = 1 L
R = Gas constant = 
T = temperature of the solution = ![20^oC=[20+273]K=293K](https://tex.z-dn.net/?f=20%5EoC%3D%5B20%2B273%5DK%3D293K)
Putting values in above equation, we get:

Hence, the pressure that must be applied to the apparatus is 0.239 atm