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miv72 [106K]
3 years ago
13

What is the maximum number of electrons that can go into each of the following sublevels?. a. 2s- . b. 4s- . c. 4p- . d. 4f- . e

. 3p-. f. 3d-. g. 5s-. h. 5p-
Chemistry
1 answer:
Eva8 [605]3 years ago
8 0
The maximum number of electrons that can go into each of the sublevels are as follows:

a. 2s- = 2 
b. 4s- = 2
c. 4p- = 6
d. 4f- = 14
e. 3p- = 6
f. 3d- = 10
g. 5s- = 2
h. 5p- = 6
Hope this answers the question. Have a nice day.
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A gas with a volume of 4.0L at a pressure of 205kPa is allowed to expand to a volume of 12.0L. What is the pressure in the conta
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Answer:

68.3 kilo Pascal is the pressure in the container.

Explanation:

To calculate the new pressure , we use the equation given by Boyle's law. This law states that pressure is inversely proportional to the volume of the gas at constant temperature.

The equation given by this law is:

P_1V_1=P_2V_2

where,

P_1\text{ and }V_1 are initial pressure and volume.

P_2\text{ and }V_2 are final pressure and volume.

We are given:

P_1=205kPa\\V_1=4.0 L\\P_2=?\\V_2=12.0 L

Putting values in above equation, we get:

P_2=\frac{P_1V_1}{V_2}

=\frac{205 kPa\times 4.0 L}{12.0 L}=68.3 kPa

68.3 kilo Pascal is the pressure in the container.

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How many moles of methane are in 7.31*10^25 molecules?
GrogVix [38]
<h3>Answer:</h3>

121 mol CH₄

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Organic</u>

  • Writing chemical compounds
  • Writing organic structures
  • Prefixes
  • Alkanes, Alkenes, Alkynes

<u>Atomic Structure</u>

  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<h3>Explanation:</h3>

<u>Step 1: Define</u>

7.31 × 10²⁵ molecules CH₄

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

<u />\displaystyle 7.31 \cdot 10^{25} \ molecules \ CH_4(\frac{1 \ mol \ CH_4}{6.022 \cdot 10^{23} \ molecules \ CH_4} ) = 121.388 \ mol \ CH_4<u />

<u />

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

121.388 mol CH₄ ≈ 121 mol CH₄

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