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3 years ago

5

the scientists tested a hypothesis on running in the rain performed only one controlled experiment that supported their hypothes

is. Can their supported hypothesis be called a theory?

1 answer:

Ulleksa [173]3 years ago

7 0

No it cannot because you would have to test it over and over again to make sure it was correct the first time.

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How far can a mother push a 20.0 kg baby carriage, using a force of 62 N, if she can only do 2920 J of work? (Round to include t

alexgriva [62]

The mathematical definition of work (W) is force (F) multiplied by distance (x). In order to determine the distance for fixed force and work the above equation needs to be rearranged to make x the subject. The work divided by the force is equal to the distance. In this case the mother can push the baby carriage by a distance equal to 2920 divided by 62, which is 47.1 metres.

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4 years ago

Do magnetic fields exist?

Art [367]

I believe yes they do hope this helps

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3 years ago

Read 2 more answers

3.1 * Consider a gun of mass M (when unloaded) that fires a shell of mass m with muzzle speed v. (That is, the shell's speed rel

kramer

Answer:

$v_s=\frac{v}{1+\frac{m}{M} }$

Explanation:

Let the shells speed with respect to ground be $v_s$

Let the shells speed with respect to ground be $v_g$

mass of shell, $m$

mass of gun, $M$

The relative velocity of shell with respect to a free unconstrained gun, $v$

According to the Newton's third law of motion the direction of the velocity of gun and shell will be in the opposite direction.

So, the relation between the relative velocity and their individual velocity will be:

$v=v_s+v_g$ ......................(1)

<u>And according to the conservation of momentum (as the condition is very close to the elastic collision):</u>

$M.v_g-m.v_s=0$

substitute the value of $v_g$ from equation (1)

$M\times (v-v_s)=m\times v_s$

$M.v-M.v_s=m.v_s$

$M.v=M.v_s+m.v_s$

$v_s=\frac{M.v}{(M+m)}$

$v_s=\frac{v}{(\frac{(M+m)}{M}) }$

$v_s=\frac{v}{1+\frac{m}{M} }$

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3 years ago

During the main sequence lifetime of a star of any mass, the core of the star will be composed mainly of _____.

EleoNora [17]

Gas my friend enjoy!!!!

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3 years ago

A projectile is launched with a velocity of 25 m/s at an angle of 20 degrees with respect to the horizontal. What is its initial

irina [24]

Answer:

b. 23.49 m/s

d. 8.55 m/s

d. .87 s

a. 40.8 m

Explanation:

The initial along the x-axis is given by the following formula:

$V_{ox} = V_{o}Cos\theta\\\\V_{ox} = (25\ m/s)(Cos\ 20^{o})\\\\V_{ox} = 23.49\ m/s$

Hence, the correct option is:

<u>b. 23.49 m/s</u>

The initial along the x-axis is given by the following formula:

$V_{oy} = V_{o}Sin\theta\\V_{oy} = (25\ m/s)(Sin\ 20^{o})\\V_{oy} = 8.55\ m/s$

Hence, the correct option is:

<u>d. 8.55 m/s</u>

Now, for the time to reach maximum height:

$t = \frac{V_{o}Sin\theta}{g}\\\\t = \frac{(25\ m/s)Sin\ 20^{o}}{9.8\ m/s^{2}}\\\\t = 0.87\ s$

Hence, the correct option is:

<u>d. .87 s</u>

<u></u>

For the range of projectile:

$R = \frac{V_{o}^{2}\ Sin\ 2\theta}{g}\\\\R = \frac{(25\ m/s)^{2}(Sin\ 40^{o})}{9.8\ m/s^{2}}\\\\R = 40.9\ m$

Hence, the closest option is:

<u>a. 40.8 m</u>

5 0

3 years ago