Answer:
a) The uniform velocity travelled by the car is 10 meters per second.
(Point b has been erased by the user)
c) The distance travelled by the car with uniform velocity is 100 meters.
Explanation:
a) Calculate the uniform velocity travelled by the car:
The uniform velocity is the final velocity (
), in meters per second, of the the uniform accelerated stage:
(1)
Where:
- Initial velocity, in meters per second.
- Acceleration, in meters per square second.
- Time, in seconds.
If we know that 
, 
and 
, then the uniform velocity is:
The uniform velocity travelled by the car is 10 meters per second.
(Point b has been erased by the user)
c) The distance travelled by the car (
), in meters, with uniform velocity is calculated by the following kinematic expression:
(2)
If we know that and 
, then the distance travelled is:
The distance travelled by the car with uniform velocity is 100 meters.
Sum up the moments of the right and the left support:
∑ M2 = 0
F1 · 3.92 m = 46 kg · 9,81 m/s² · 4.46 m + 250 kg · 9.81 m/s² · 1.96 m
F 1 · 3.92 = 2012.6 + 4806.9
F 1 = 6819.5 : 3.92
F 1 = 1739.67 N
∑ M 1 = 0
F 2 · 3.92 m + 46 kg · 9.81 m/s² · 0.54 m = 250 kg · 9.81 m/s² · 1.96 m
F 2 · 3.92 + 243.68 = 4806.9
F 2 · 3.92 = 4563.22
F 2 = 4563.22 : 3.92
F 2 = 1164 N
Answer: The forces on the beam are: F 1 = 1739.67 N and F 2 = 1164 N.
Answer:
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Explanation:
This is ur answer actually I just took it from Go ogle
