To develop the problem, we require the values concerning the conservation of momentum, specifically as given for collisions.
By definition the conservation of momentum tells us that,![m_1V_1+m_2V_2 = (m1+m2)V_f](https://tex.z-dn.net/?f=m_1V_1%2Bm_2V_2%20%3D%20%28m1%2Bm2%29V_f)
To find the speed at which the arrow impacts the apple we turn to the equation of time, in which,
![t= \sqrt{\frac{2h}{g}}](https://tex.z-dn.net/?f=t%3D%20%5Csqrt%7B%5Cfrac%7B2h%7D%7Bg%7D%7D)
The linear velocity of an object is given by
![V=\frac{X}{t}](https://tex.z-dn.net/?f=V%3D%5Cfrac%7BX%7D%7Bt%7D)
Replacing the equation of time we have to,
![V_f = \frac{X}{t}\\V_f =\frac{X}{\sqrt{\frac{2h}{g}}}\\V_f = \frac{6.9}{\sqrt{\frac{2(1.85)}{9.8}}}\\V_f = 11.23m/s](https://tex.z-dn.net/?f=V_f%20%3D%20%5Cfrac%7BX%7D%7Bt%7D%5C%5CV_f%20%3D%5Cfrac%7BX%7D%7B%5Csqrt%7B%5Cfrac%7B2h%7D%7Bg%7D%7D%7D%5C%5CV_f%20%3D%20%5Cfrac%7B6.9%7D%7B%5Csqrt%7B%5Cfrac%7B2%281.85%29%7D%7B9.8%7D%7D%7D%5C%5CV_f%20%3D%2011.23m%2Fs)
Velocity two is neglected since there is no velocity of said target before the collision, thus,
![m_1V_1 = (m1+m2)V_f](https://tex.z-dn.net/?f=m_1V_1%20%3D%20%28m1%2Bm2%29V_f)
Clearing for m_2
![m_2 = \frac{m_1V_1}{V_f}-m_1\\m_2 = \frac{(0.102)(26.7)}{11.23}-0.102\\m_2 = 0.1405KG= 140.5g](https://tex.z-dn.net/?f=m_2%20%3D%20%5Cfrac%7Bm_1V_1%7D%7BV_f%7D-m_1%5C%5Cm_2%20%3D%20%5Cfrac%7B%280.102%29%2826.7%29%7D%7B11.23%7D-0.102%5C%5Cm_2%20%3D%200.1405KG%3D%20140.5g)
Answer:
The specific heat for the metal is 0.466 J/g°C.
Explanation:
Given,
Q = 1120 Joules
mass = 12 grams
T₁ = 100°C
T₂ = 300°C
The specific heat for the metal can be calculated by using the formula
Q = (mass) (ΔT) (Cp)
ΔT = T₂ - T₁ = 300°C - 100°C = 200°C
Substituting values,
1120 = (12)(200)(Cp)
Cp = 0.466 J/g°C.
Therefore, specific heat of the metal is 0.466 J/g°C.
There are NO true statements on the list you provided.
4 for sure because you dont want anything spilling on you or others that is harmful.
Answer:
A (2066,6 N)
Explanation:
Use the Work formula
62.000J = F . 30
62.000/30 = 2066,6 N
The amout of time it took to move the rock doesn´t matter at all.
It is called a distraction variable, We don´t need it to solve the problem it is there just to confuse.