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Dennis_Churaev [7]

3 years ago

7

What is the most abundant element in the universe? A. helium B. hydrogen C. carbon

2 answers:

Naya [18.7K]3 years ago

3 0

The answer is Carbon

poizon [28]3 years ago

3 0

It's C ......................

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Hoochie [10]

Answer:

Young's modulus of this tendon is $9.03\times 10^6\ N/m^2$ .

Explanation:

Given that,

Length of the tendon, l = 19 cm

It is stretched by 4.5 mm, $\Delta l=4.5\ mm$

Force, F = 11.3 N

Average diameter, d = 8.2 mm

Radius, r = 4.1 mm

The formula of Young's modulus of this tendon is given by :

$Y=\dfrac{Fl}{\Delta l A}\\\\Y=\dfrac{11.3\times 0.19}{4.5\times 10^{-3}\times \pi (4.1\times 10^{-3})^2}\\\\Y=9.03\times 10^6\ N/m^2$

So, the Young's modulus of this tendon is $9.03\times 10^6\ N/m^2$ . Hence, this is the required solution.

4 0

4 years ago

If you could shine a very powerful flashlight beam toward the Moon, estimate the diameter of the beam when it reaches the Moon.

grin007 [14]

To develop this problem it is necessary to apply the Rayleigh Criterion (Angular resolution)criterion. This conceptos describes the ability of any image-forming device such as an optical or radio telescope, a microscope, a camera, or an eye, to distinguish small details of an object, thereby making it a major determinant of image resolution. By definition is defined as:

$\theta = 1.22\frac{\lambda}{d}$

Where,

$\lambda$ = Wavelength

d = Width of the slit

$\theta$ = Angular resolution

Through the arc length we can find the radius, which would be given according to the length and angle previously described.

The radius of the beam on the moon is

$r = l\theta$

Relacing $\theta$

$r = l(\frac{1.22\lambda}{d})$

$r = 1.22\frac{l\lambda}{d}$

Replacing with our values we have that,

$r = 1.22*(\frac{(384*10^3km)(\frac{1000m}{1km})(550*10^{-9}m)}{7*10^{{-2}}})$

$r = 3680.91m$

Therefore the diameter of the beam on the moon is

$d = 2r$

$d = 2 * (3690.91)$

$d = 7361.8285m$

Hence, the diameter of the beam when it reaches the moon is 7361.82m

8 0

4 years ago

How do I find time?

kari74 [83]

<u>Answer:</u> 3

H = 45 m ,

time required for the stone

S = u.t+(1/2) g.t²

45 = (1/2) 9.81. t² since u( initial velocity) = 0 ; S =H.

t² = 9.17 s

<em> t = 3.02 s </em>

therefore answer is 3 m/s

<em> if you satisfy with explanation, please give brainiest ; </em>

6 0

3 years ago

Calculate the momentum for a 0:2 kg rifle bullet traveling 300m/a

Ksenya-84 [330]

Given data

mass (m) = 0.2 Kg ,

velocity (v) =300 m/s ,

calculate momentum <em>(p) = m × v </em>

<em> = 0.2 × 300</em>

<em> </em><em> P = 60 Kg. m/s</em>

<em> Momentum of the bullet is 60 Kg. m/s..</em>

7 0

4 years ago

A simple pendulum has a bob of mass M. The bob is on a light string of length . The string is fixed at C. At position A, the str

Vlad [161]

Answer:

$v=\sqrt{2gL}$

Explanation:

mass of bob = M

string is fixed at C, at position A the string is horizontal and at position B teh string is vertical.

Let the length of the string is L.

At the point C, it has maximum potential energy which is equal to

U = M x g x L ..... (1)

At the position B, it has maximum kinetic energy and the velocity is v.

K = 1/2 Mv² ...... (2)

According to the conservation of energy

The potential energy at the position A is equal to the kinetic energy at position B.

M x g x L = 1/2 M x v²

v² = 2 x g x L

$v=\sqrt{2gL}$

6 0

3 years ago

Read 2 more answers