Oh ya the correct answer for this is B I think because structure B
Answer:
25m/s
Steps:
<em> First, The equation v= u + a * t shows us what we need to find, (the finale velocity). </em>
<em />
Second, we substitute the values given:
v= 9m/s + 4m/s2 * 4s
Last, We calculate the values:
Multiply 4m/s2 * 4s = 16m/s
Add 9m/s + 16m/s
<u></u>
<u>Answer: 25m/s</u>
Hope this helps :)
A projectile fired upward from the Earth's surface will usually slow down, come momentarily to rest, and return to Earth. For a certain initial speed, however it will move upward forever, with its speed gradually decreasing to zero just as its distance from Earth approaches infinity. The initial speed for this case is called escape velocity. You can find the escape velocity v for the Earth or any other planet from which a projectile might be launched using conservation of energy. The projectile of mass m leaves the surface of the body of mass M and radius R with a kinetic energy Ki = mv²/2 and potential energy Ui = -GMm/R. When the projectile reaches infinity, it has zero potential energy and zero kinetic energy since we are seeking the minimum speed for escape. Thus Uf = 0 and Kf = 0. And from conservation of energy,
Ki + Ui = Kf + Uf
mv²/2 -GMm/R = 0
∴ v = √(2GM/R)
This is the expression for escape velocity.
Answer:
oo.p i wish I could answer that
Explanation:
Answer:
![r_{cm}=[12.73,12.73]cm](https://tex.z-dn.net/?f=r_%7Bcm%7D%3D%5B12.73%2C12.73%5Dcm)
Explanation:
The general equation to calculate the center of mass is:
Any differential of mass can be calculated as:
Where "a" is the radius of the circle and λ is the linear density of the wire.
The linear density is given by:
So, the differential of mass is:
Now we proceed to calculate X and Y coordinates of the center of mass separately:
Solving both integrals, we get:
Therefore, the position of the center of mass is:
