When a carnivore eats an herbivore
Answer:
We would need 10 mL of the concentrated CaCl₂ stock solution, and 30 mL of water.
Explanation:
To solve the question asked we can use the C₁V₁=C₂V₂ equation, where:
We <u>solve for V₁</u>:
We would need 10 mL of the concentrated CaCl₂ stock solution, and (40-10) 30 mL of water.
The answer is A) Sodium is an Alkali metal and is in group IA with an ionic charge of +1. While chlorine, Cl, is a halogen and is in group VIIA with a charge of -1. These will form NaCl(s).
Mass of solute = 35 grams
Mass of solution = mass of nacl + mass of water = 35.8 + 184 = 219.8 grams
Concentration = mass of Nacl x 100/mass of solution.
= 35x100/219.8 = 15.92%.
Hope this helps you.
Answer:
Sample A - mixture
Sample B- Mixture
Explanation:
Looking at sample A, we can see that as water was poured over sample A, the sample was separated into its components as the powder disappeared leaving behind a gritty black sand-like material on the surface of the paper. A separation of the mixture has taken place.
In sample B, we can clearly see that it is a mixture because the amount of solid recovered is much less than the total mass of the solid put into the beaker. The sample must have been separated into its components.
