Answer:
The molar mass of the unknown gas is 100.4 g/mol
Explanation:
Step 1: Data given
Molar mass of argon = 39.95 g/mol
After filling with argon the flask gained 3.221 grams
After filling with an unknown gas, the flask gained 8.107 grams
Step 2: Calculate the molar mass of the unknown gas
The gas with the higher molar mass will have the higher density.
Ar - 3.224 g; molar mass = 39.95 g/mol
X = 8.102 g; molar mass = ??
Molar mass of the unknown gas = 8.102g X *(39.95 g/mol / 3.224 g) = 100.4 g/mol
The molar mass of the unknown gas is 100.4 g/mol
Answer:
The correct answer is <em>d. At equilibrium, the forward reaction and reverse reaction will have the same reaction rate.</em>
Explanation:
When a reaction begins, the reactants combine to form products. At the same time of product formation, the convertion of products into reactants also occur. The reaction reaches <em>chemical equilibrium </em>when the rate of forward reaction (the convertion of reactant into products) is equal to the rate of reverse reaction (the convertion of product into reactants). Upon this state, the concentration of reactants and products do not change in time (that does not mean that the concentration of reactants and products are equal, but that once the chemical equilibrium is reached, their concentrations at this point will not vary with the time because the forward and reverse reactions are occuring at the same velocity).
Answer:
Approximately
.
Explanation:
Convert both volumes to standard units (that is: liters.)
.
.
Number of moles of
initially present (in the
solution at
.)
.
Number of moles of
from the titration:
.
neutralizes
at a
ratio:
.
Hence,
.
.
Answer:
So the answer would be 10 moles
Explanation:
1) Start with the molecular formula for water: 
2) If there are 10 moles of water use a mole ratio to calculate the moles of oxygen it would produce.
(This question is... interesting... since they chose an element that is diatomic in free state so It could TECHNICALLY be two answers, moles of O or moles of
)
The mole ratio is 1 moles of
to 1 moles of O. This is because the coefficient for oxygen in water is simple 1, so the ratio is 1:1.
3) that means if 10 moles of water decompose, they decompose into 10 moles of
and 10 moles of O.
Extra:
About what I was saying before about the question being slightly interesting:
10 moles of pure oxygen is produced but free state oxygen exists as
so it could possibly be 10 OR 5! However, notice it says elements. This leads me to believe the answer is 10 (monatomic oxygen) instead of 5 (free state/diatomic oxygen).
I hope this helps!
Somewhat false
observations can be made of a model of the statue of liberty, say, or in real line