1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
sertanlavr [38]
3 years ago
8

3. A cheetah is known to be the fastest mammal on Earth, at least for short

Physics
1 answer:
Kay [80]3 years ago
4 0

Answers:

a) 198,55 s

b) 4687.98 m

Explanation:

a) Speed v is defined as the variation of the position (distance traveled d)of a body or object with time t:

v=\frac{d}{t} (1)

We are told the cheetah runs a distance of  d=5.50(10)^{2}m=550m with a speed v=10\frac{km}{h}=2.77\frac{m}{s} (Knowing 1km=1000m and 1h=3600s), and we need to find the time it takes to travel that distance.

This means we have to find t from (1):

t=\frac{d}{v} (2)

t=\frac{550m}{2.77\frac{m}{s}} (3)

t=198.55s (4)

b) Now, if we want to know the distance the cheetah will cover with v=85\frac{km}{h}=23.61\frac{m}{s} in t=198.55s, we have to isolate d from (1):

d=v.t (5)

d=(23.61\frac{m}{s})(198.55s) (6)

Finally:

d=4687.98m

You might be interested in
After a while, the car started to go around a long bend, still maintaining its constant speed of 55 miles per hour. Is there a n
sukhopar [10]

Answer:

4) True. The change of direction needs an unbalanced force

Explanation:

Let us propose the resolution of the problem using Newton's second law.

    F = m a

As the car is spinning the acceleration is centripetal

    a = v2.r

   

    F = m v2 / r

We can see that as the velocity of a vector even if its module does not change, the change of direction requires an external force.

Now we can analyze the statement if they are true or false

1) and 3) False, even when the speed changes, the direction changes

2) False with the speed change can be determined

4) True. The change of direction needs an unbalanced force

5) False are different things. the direction is where it is going and the speed is the magnitude of the vector

6 0
3 years ago
A vertical wire carries current in the upward direction. an electron is traveling parallel to the wire. what is the angle α betw
Luden [163]
Angle α between the velocity of theelectron and the magnetic field of the wire will be 90 degree
7 0
3 years ago
The figure shows a 1 cm cube that has a mass of 1 gram. Calculate the density of the cube in kg/m³.
dolphi86 [110]
Density = 1 g/cm^3 = 1000 Kg/m^3
3 0
3 years ago
Give at least one fact about subatomic particles
victus00 [196]

Answer:

- Particles smaller than atoms are called subatomic particles .

- There are three famous subatomic particles, proton, neutron and electron .

- The study of sub atomic particles are called particle physics

- These particles can be divided as Brayons and Leptons

- These particles are often held together by one of the four fundamental particles ( Weak force, strong force, electromagnetic force, gravitational force).

6 0
3 years ago
Two point charges, a +45nC charge X and a +12nC charge Y are separated by a distance of 0.5m.
Gnoma [55]

A) Calculate the resultant electric field strength at the midpoint between the charges.

Qx is the charge at X and Qy is the charge at Y.

E at midpoint = k×Qx/0.25² - k×Qy/0.25²

k = 9×10⁹Nm²C⁻², Qx = 45nC, Qy = 12nC

E = 4752N/C

Well done.

B) Calculate the distance from X at which the electric field strength is zero.

Let D be some point between X and Y for which the net E field is 0.

Let d be the distance from X to D.

Set up the following equation:

E at D = k×Qx/d² - k×Qy/(0.5-d)² = 0

Do some algebra to solve for d:

k×Qx/d² = k×Qy/(0.5-d)²

Qx/d² = Qy/(0.5-d)²

Qx(0.5-d)² = Qyd²

(0.5-d)√Qx = d√Qy

0.5√Qx-d√Qx = d√Qy

d(√Qx+√Qy) = 0.5√Qx

d = (0.5√Qx)/(√Qx+√Qy)

Plug in Qx = 45nC, Qy = 12nC

d ≈ 330mm

C) Calculate the magnitude of the electric field strength at the point P on the diagram below.

First determine the angles of the triangle. The sides of the triangle are 0.3m, 0.4m, and 0.5m, so this is a right triangle where the angle between the 0.3m and 0.4m sides is 90°

∠Y = tan⁻¹(0.4/0.3) = 53.13°

∠X = 90-∠Y = 36.87°

Determine the horizontal component of E at P:

Ex = E from Qx × cos(∠X) - E from Qy × cos(∠Y)

Ex = k×Qx/0.4²×cos(36.87°) - k×Qy/0.3²×cos(53.13°)

Ex = 1305N/C

Determine the vertical component of E at P:

Ey = E from Qx × sin(∠X) - E from Qy × sin(∠Y)

Ey = k×Qx/0.4²×sin(36.87°) - k×Qy/0.3²×sin(53.13°)

Ey = 2479N/C

Use the Pythagorean theorem to determine the magnitude of E at P:

E = √(Ex²+Ey²)

E ≈ 2802N/C

4 0
3 years ago
Other questions:
  • An airplane heads northeast at an airspeed of 700 km/hr, but there is a wind blowing from the west at 60 km/hr. In what directio
    8·1 answer
  • Is the
    15·1 answer
  • 1) ________ is a force that you can fell with your feet
    13·1 answer
  • A cube of side 6.50 cm is placed in a uniform field E = 7.50 × 10^3 N/C with edges parallel to the field lines (field enters the
    14·2 answers
  • a child sleds down a steep snow-covered hill with an acceleration of 3.94 m/s^2. if her initial speed is 0.0m/s and her final sp
    15·1 answer
  • A thin film of oil rests on an inclined plane
    15·1 answer
  • A charge Q exerts a 1.2 N force on another charge q. If the distance between the charges is doubled, what is the magnitude of th
    7·1 answer
  • What machine would benefit from slowing lights speed
    12·1 answer
  • A skateboarder, starting from the top of a ramp 4,5 m above the ground, skates down the ramp. The mass of the skateboarder and h
    7·1 answer
  • A load of 50N attached to a spring hanging vertically stretches the spring is 5cm . The spring is now placed horizontally on a t
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!