distance traveled by a uniformly accelerated bike is given as
here we know that
now we will have from above equation
so it will cover the total distance of 300 m
Answer:
See the attached pictures for detailed steps.
Explanation:
m = mass of the ice added = ?
M = mass of water = 1.90 kg
= specific heat of the water = 4186 J/(kg ⁰C)
= specific heat of the ice = 2000 J/(kg ⁰C)
= latent heat of fusion of ice to water = 3.35 x 10⁵ J/kg
= initial temperature of ice = 0 ⁰C
= initial temperature of water = 79 ⁰C
T = final equilibrium temperature = 8 ⁰C
using conservation of heat
Heat gained by ice = Heat lost by water
m (T - ) + m = M ( - T)
inserting the values
m (4186) (8 - 0) + m (3.35 x 10⁵ ) = (1.90) (4186) (79 - 8)
m = 1.53 kg
Answer:
distance when the weight is 8 kg is 26.66 cm
Explanation:
given data
distance d2 = 10 cm
weight w2 = 3 kg
weight w1 = 8 kg
to find out
distance when the weight is 8 kg
solution
we consider here distance d1 when weight is 8 kg
so equation will be
d1/d2 = w1/w2
d/10 = 8/ 3
so d = 8/3 × 10
so d = 26.66
distance when the weight is 8 kg is 26.66 cm
Answer:
B. Longer than t s,
Explanation:
Gravitational accln on earth is 9.8 m/s^2,
and one you provided as on moon is 1.6 m/s^2
that mean on moon gr. accl. is lesser!
now the time taken on earth will be lesser cuz from the same height if you drop the object from rest!
since accln on earth is higher,the object will attain higher velocity as compare to that of on moon!
✌️:)
