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Mice21 [21]
3 years ago
13

What is the force of an object that has a mass of 42 kg and an acceleration of 3 m/s22?

Physics
1 answer:
Ivanshal [37]3 years ago
5 0

Answer:

\boxed {\boxed {\sf 126 \ Newtons}}

Explanation:

According to Newton's 2nd Law of Motion, force is the product of mass and acceleration.

F=ma

The mass is 42 kilograms and the acceleration is 3 meters per square second.

m= 42 \ kg \\a= 3 \ m/s^2

Substitute the values into the formula.

F= 42 \ kg * 3 \ m.s^2

Multiply.

F= 126 \ kg*m/s^2

  • 1 kilogram meter per square second is equal to 1 Newton.
  • The answer we calculated is equal to 126 Newtons.

F= 126 \ N

The object's force is <u>126 Newtons.</u>

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Answer:

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                                  w = 7.27 * 10^-5 rad/s

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                                 v1 = R*w

                                 v1 = (6.37 * 10 ^6)*(7.27 * 10^-5)

                                 v1 = 463.1 m/s

- The angle θ subtended by a point on earth's surface 1/5 th between the equator and the pole wrt equator is.

                                 π/2  ........... s

                                 x     ............ 1/5 s

                                 x = π/2*5 = 18°    

- The radius of the earth R' at point where θ = 18° from the equator is:

                                R' = R*cos(18)

                                R' = (6.37 * 10 ^6)*cos(18)

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- The speed of the point where θ = 18° from the equator v2 can be determined from the linear and rotational motion kinematic relation.

                              v2 = R'*w

                              v2 = (6058230.0088)*(7.27 * 10^-5)

                              v2 = 440.433 m/s

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