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2 years ago

What is the force of an object that has a mass of 42 kg and an acceleration of 3 m/s22?

Physics

1 answer:

Ivanshal [37]2 years ago

5 0

Answer:

$\boxed {\boxed {\sf 126 \ Newtons}}$

Explanation:

According to Newton's 2nd Law of Motion, force is the product of mass and acceleration.

$F=ma$

The mass is 42 kilograms and the acceleration is 3 meters per square second.

$m= 42 \ kg \\a= 3 \ m/s^2$

Substitute the values into the formula.

$F= 42 \ kg * 3 \ m.s^2$

Multiply.

$F= 126 \ kg*m/s^2$

1 kilogram meter per square second is equal to 1 Newton.
The answer we calculated is equal to 126 Newtons.

$F= 126 \ N$

The object's force is 126 Newtons.

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2 years ago

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2 years ago

how much gravitational potential energy do you give a 70 kg person when you lift him up 3 m in the air?

SCORPION-xisa [38]

Given gravitational potential energy when he's lifted is 2058 J.

Kinetic energy is transferred to the person.

Amount of kinetic energy the person has is -2058 J

velocity of person = 7.67 m/s².

<h3>Explanation:</h3>

Given:

Weight of person = 70 kg

Lifted height = 3 m

1. Gravitational potential energy of a lifted person is equal to the work done.

$PE_g=W=m\times g\times h\\Acceleration due to gravity = g = 9.8 \ m/s^2 \\PE_g= m = m\times g\times h= 70\times 9.8 \times 3 = 2058\ kg.m/s^2 = 2058\ J$

Gravitational potential energy is equal to 2058 Joules.

2. The Gravitational potential energy is converted into kinetic energy. Kinetic energy is being transferred to the person.

3. Kinetic energy gained = Potential energy lost = $-PE_g = -2058\ kg.m/s^2$

Kinetic energy gained by the person = (-2058 kg.m/s²)

4. Velocity = ?

Kinetic energy magnitude= $\frac{1}{2} m\times v^2 = m\times g \times h$

Solving for v, we get

$v=\sqrt{2gh} =\sqrt{2\times 9.8 \times 3} = \sqrt{58.8} = 7.67 m/s^2$

The person will be going at a speed of 7.67 m/s².

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2 years ago