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vlabodo [156]
3 years ago
12

Light traveling through air strikes the surface of the four different materials below. which material reflects light but doesn't

refract it?
Options:
A-Metal Spoon
B-Water Droplets
C-Diamond
D-Prism
Physics
2 answers:
Dmitriy789 [7]3 years ago
7 0
B....……................
lisov135 [29]3 years ago
5 0
It A) a metal spoon hope this help

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What are the products of coal​
Sonja [21]

Answer:

coal tar is one of the product of coal

4 0
3 years ago
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A small loop of area A = 5.5 mm2 is inside a long solenoid that has n = 919 turns/cm and carries a sinusoidally varying current
Tema [17]

Answer:410.90\times 10^{-6} V

Explanation:

Given

A=5.5 mm^2

n=919 turns/cm\approx 85400 turns/m

\omega =226 rad/s

According to the Faraday law of induction, induced emf is given by

E=-\frac{\mathrm{d} \phi _B}{\mathrm{d} t}

Magnetic field \phi _B=B\cdot A

B=\mu _0ni=\mu _0ni_osin\left ( \omega t\right )

B=4\pi \times 10^{-7}\times 85400\times 3.08\times \sin (226t)

B=0.3305\sin (226t)

\phi _{B}=0.3305\times \sin (226t)\times 5.5\times 10^{-6}

\phi _{B}=1.818\times 10^{-6}\sin (226t)

E=-\frac{\mathrm{d} \phi _B}{\mathrm{d} t}

E=-1.818\times 10^{-6}\times 226\cos (226t)

E=-410.90\times 10^{-6}\cos (226t)

Amplitude of EMF induced=410.90\times 10^{-6} V

8 0
3 years ago
The bell rings and a physics student heads to class. They stop to talk to a few friends. They slow
grin007 [14]

Answer:

420m

Explanation:

Given parameters:

Time  = 5minutes

Average speed  = 1.4m/s

Unknown:

Distance covered  = ?

Solution:

Speed is the rate of change of distance with time.

 Mathematically;

              Speed  = \frac{distance}{time}  

    Distance  = speed x time

 

Insert the parameters and solve;

   Convert the time to seconds;

              1 minute = 60s

               5 minute = 5  x 60 = 300s

So,

   Insert the parameters and find the distance;

     Distance  = 300 x 1.4  = 420m

3 0
2 years ago
A ball of mass m falls vertically, hits the floor with a speed ui , and rebounds with a speed u f . what is the magnitude of the
Sholpan [36]

Answer:

Change of momentum = M (Vf - (-Vi))   where V represents the scalar speeds of the ball or

I = M (ui + uf)  and I is the impulse ΔM V = I     Force = Change in Momentum

5 0
2 years ago
An object is dropped from a bridge. A second object is thrown downward 1.48 s later. They both reach the water 48.1 m below at t
pashok25 [27]

To solve this problem we will apply the linear motion kinematic equations. With the data provided we will calculate the time of the first object to fall. Later we will get the time difference between the two. This difference will allow us to find the free fall distance. Through the distance we will find the initial velocity, that is,

x = v_0 t +\frac{1}{2}at^2

48.1 = 0*t + \frac{1}{2} (9.8)t^2

t = 3.13s

The second object is thrown downward at one second later and it meets the first object at the water is

t' = 3.13 -1.48

t' = 1.65s

The distance of the object will travel due to free fall acceleration is

x = v_0 t+\frac{1}{2} at^2

x = 0*(1.65) +\frac{1}{2}(9.8)(1.65)^2

x = 13.34m

The distance of the object will travel due to its initial velocity is

v_0 = \frac{d_0}{t}

d_0 = v_0 t

48.1-13.34 = v_0 (1.65)

v_0 = 21.06m/s

Therefore the initial speed of the second object is 21.06m/s

8 0
3 years ago
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