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vlabodo [156]
3 years ago
12

Light traveling through air strikes the surface of the four different materials below. which material reflects light but doesn't

refract it?
Options:
A-Metal Spoon
B-Water Droplets
C-Diamond
D-Prism
Physics
2 answers:
Dmitriy789 [7]3 years ago
7 0
B....……................
lisov135 [29]3 years ago
5 0
It A) a metal spoon hope this help

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A 2000kg suv accelerates from rest at a rate of 3.00m/s^2. The total amount of force resisting its motion 1500N. How much force
choli [55]

The total force that the SUV exerts is:

F = 2000 kg * 3 m/s^2

F = 6000 N

 

Since a resisting force amounting to 1500 N is exerted, then the force exerted by the SUV tires is:

F tire = 6000 N – 1500 N

F tire = 4500 N

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Astronomers can now report that active star formation was going on at a time when the universe was only 20% as old as it is toda
disa [49]

Answer:

First, as you may know, the light travels at a given velocity.

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And we know that:

distance = velocity*time

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Which equation is true of an atom with no elctrical charge
Paladinen [302]

Answer:

Atoms are composed of electrons (charge -1), protons (charge +1), and neutrons (no charge). So in a neutral atom the correct answer is "D".

3 0
3 years ago
The earth has a vertical electric field at the surface,pointing down, that averages 102 N/C. This field is maintained by various
Schach [20]

Answer:

q  =  -461532.5 \ C

Explanation:

From the question we are told that

     The  electric filed is  E  =  102 \ N/C  

Generally according to Gauss law

=>   E  A  =  \frac{q}{\epsilon_o }

Given that  the electric field is pointing downward  , the equation become

    - E  A  =  \frac{q}{\epsilon_o }

Here   q is the excess charge on the surface of the earth

          A is the surface  area of the of the earth which is mathematically represented as

     A  =  4\pi r^2

Where r is the radius of the earth which has a value r = 6.3781*10^6 m

 substituting values

    A  = 4 * 3.142  *   (6.3781*10^6 \ m)^2

    A  =5.1128 *10^{14} \ m^2

So

   q  =  -E  * A  *  \epsilon _o

Here \epsilon_o s the permitivity of free space with value

          \epsilon_o  =  8.85*10^{-12} \  m^{-3} \cdot kg^{-1}\cdot  s^4 \cdot A^2

substituting values

     q  =  -102  * 5.1128 *10^{14}  *  8.85 *10^{-12}

     q  =  -461532.5 \ C

6 0
3 years ago
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