Answer:
(a)
(b) 5 A
Solution:
As per the question:
Radius of the circular plate, R = 9 cm = 0.09 m
Distance, d = 2.0 mm =
At , current, I = 5 A
Now,
Area, A =
We know that the capacitance of the parallel plate capacitor, C =
Also,
Also,
Now,
(a) The rate of change of electric field:
where
(b) To calculate the displacement current:
where
= Rate of change of flux
Answer:
Let the power delivered by the sound wave be 'P'
Intensity by definition is the power delivered per unit area.
i.e. I =
dA
dP
;
In spherical polar coordinate system dA = r
2
Ω
I =
r
2
Ω
dP
;
I ∝
r
2
1
So if distance increases 3 fold. The Intensity becomes
9
1
times the initial
Answer:
+b±√b² - 4ac /2a
0.6t ± √36-36/2a
Explanation:
Work done = 1/2 mv² where v = (1.2)²
Therefore, 1/2m(1.2)ω mgh
1/2m (1.2)² = 0.4 × m ×10 5
s = 1.44 / 2.4 = 1.44 / 8
S = ut - 1/2gt²
Where u = 1.2
g = 0.9 × 10
Therefore,
1.8 = 1.2v-2t²
2t²c-1.2t+1.8 = 0
t² - 0.6t + 0.9 = 0
0.6t ± √36-36/2a
Solving this further, we make use of the formula
+b±√b² - 4ac /2a
Answer:
Rovers, unmanned space probes, modern instruments,
Explanation:
Answer:
2452.5 N/m^2
Explanation:
given:
density =500kg/m^3
viscosity = 10 Pa-s
diameter of tube= 2 m
and L be length
since gravity is the only force shear force will balance it
so we can write
mg=
A=
m=
therefore
putting values we get
calculating we get 2452.5 N/m^2